4 years ago

precalculus find two numbers whose product is -16 such that the sum of their squares is as small as possible

1 answer:

6 0

The answer is -4 and 4, since if you multiply the two, you get the product “-16” and if you add the squares of the two, you would get 32. The other options would be +or- 16 and 1, or 8 and 2, but adding the squares of those would result in a number larger than 32, therefore, the answers are 4 and -4.

Answer: 4 and -4

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3 years ago

If -7 +3x=-25, what is the value of x^2-6x+9

Musya8 [376]

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3 years ago

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3 years ago

— 12 – 6р – (-2)<br> help pls

baherus [9]

Answer: -6P - 10

Step-by-step explanation:

STEP 1. -12 - 6P + 2

STEP 2. -6P + ( -12 + 2 )

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3 years ago

Divide 33 photos into two groups so the ratio is 4 to 7

Advocard [28]

4 to 7
or
4+7= 12
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x=3
so,
(4×3)+(7×3)=33
12+21=33
or
12 and 21.
hope it helped

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3 years ago