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3 years ago

Can someone please help

Mathematics

1 answer:

Nonamiya [84]3 years ago

3 0

Answer:

Step-by-step explanation: do what it says go to a supermarket lol

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A number divided by 40 has a quotient of 6 with a remainder of 16

exis [7]

256 divide by 40 that will give you the quotient of 6 with a remainder of 16

3 0

3 years ago

Read 2 more answers

26.72 ÷ 4.7 (Round to the nearest hundredth)

padilas [110]

Answer:

6 0r 5.6 rounded to the nearest hundredth

Step-by-step explanation:

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2 years ago

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At midnight, the temperature was 34°F. By 6:00 a.m. it had dropped 8°, and by noon it had increased by 11°. What was the tempera

olga_2 [115]

Answer:

The temperature at noon was 37 °F.

Step-by-step explanation:

Given:

Temperature at midnight is 34 °F.

Reduction in temperature by 6:00 a.m. is 8°. So, temperature after reduction is given as the difference in temperature at midnight and morning.

Therefore, temperature by 6:00 a.m. in the morning is given as:

Reduced temperature = Midnight temperature - Reduction in temperature.

Reduced temperature = 34 °F - 8 °F = 26 °F.

Now, by noon, the temperature is increased by 11 °F. Therefore, the final temperature by noon is addition of 11 degree to the temperature that was in the morning. Therefore,

Temperature at noon = Temperature in morning + Increase in temperature.

Temperature at noon = 26 °F + 11 °F = 37 °F.

So, the temperature at noon is a 3 °F increase to the temperature at midnight and is equal to 37 °F.

7 0

3 years ago

Atmospheric pressure decreases by about 11.8% for every 1000 meters you climb. The pressure at sea level is 1013 millibars (a un

erica [24]

At sea level, the pressure is 1013, that's when the altitude is at 0, sea level, let's see

$\bf \textit{Periodic Exponential Decay}\\\\
A=I(1 - r)^{\frac{t}{p}}\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &1013\\
I=\textit{initial amount}\\
r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\
t=\textit{meters climbed}\to &0\\
p=period\to &1000
\end{cases}
\\\\\\
1013=I(1-0.118)^{\frac{0}{1000}}\implies 1013=I\cdot 1\implies 1013=I$

so, the inital amount is 1013, when t = 0,

$\bf \textit{Periodic Exponential Decay}\\\\
A=I(1- r)^{\frac{t}{p}}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &1013\\
r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\
t=\textit{meters climbed}\to &t\\
p=period\to &1000
\end{cases}
\\\\\\
A=1013(1-0.118)^{\frac{t}{1000}}\implies A=1013(0.882)^{\frac{t}{1000}}$

now, to check the atmospheric pressure at 4000, simply set t = 4000, to get A.

7 0

3 years ago

Regina has two electronic files. One has a size of 3.15 MB and the other has a size 4.89 MB. What is the best estimate of the to

timurjin [86]

So,

If you are rounding to the nearest tenth of a MB, then it would look like this:
3.2 + 4.9 = 8.1 MB
Because in 3.15, 5 is greater than or equal to 5, and in 4.89, 9 is greater than or equal to 5.

If you are rounding to the nearest MB, then it would look like this:
3 + 5 = 8 MB
Because in 3.15, 1 is less than 5, and in 4.89, 8 is greater than or equal to 5.

In my opinion, I would mentally add them to get 8.14 MB, because if you do math well, you can mentally add these things like second nature. This is really helpful when you go shopping, which I'll bet you will be doing profusely.

6 0

3 years ago