When reflecting across the Y axis, the Y values remain the same.
Now if you were reflecting across Y = 0, the x values would just be inverse ( opposite signs).
So this triangle if reflected across Y = 0 the new vertices would be (4,4) (2,3) and (5,2)
Now since the reflection line is y = -1, which is a one unit shift to the left of y = 0, subtract 1 unit from each X value.
The locations are now: A'(3,4), B'(1,3) and C'(4,2)
I believe the answer will always be one.
Heres an example: 5/8 • 8/5 = 1
Answer:
the answer is 140 , please let me know if I am wrong.
Answer: y = 3x + 1
<u>Step-by-step explanation:</u>
The equation is in Slope-Intercept format: y = mx + b where
- m is the slope <em>(difference in y's over difference in x's)</em>
- b is the y-intercept <em>(value of y when x = 0)</em>
b = 1 <em>refer to the table that shows y = 1 when x = 0</em>
Now input m = 3 and b = 1 into the Slope-Intercept formula:
y = 3x + 1
Answer: 5x ( x - 5y )
Step-by-step explanation:
