Question

How do I factor completely 8y^2+4y-6ay-3a

Answer 1

Answer:

(2y+1)(4y+3a)

Step-by-step explanation:

The given expresion is:

$8 {y}^{2} + 4y - 6ay - 3a$

We need to factor by grouping.

$4y(2y + 1) - 3a(2y + 1)$

$(2y + 1)(4y - 3a)$

Now we cannot factorize further.

Therefore the complete factorization of the given expresion is (2y+1)(4y-3a)