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noname [10]
4 years ago
6

How do I factor completely 8y^2+4y-6ay-3a

Mathematics
1 answer:
Papessa [141]4 years ago
6 0

Answer:

(2y+1)(4y+3a)

Step-by-step explanation:

The given expresion is:

8 {y}^{2}  + 4y - 6ay - 3a

We need to factor by grouping.

4y(2y + 1) - 3a(2y + 1)

(2y + 1)(4y - 3a)

Now we cannot factorize further.

Therefore the complete factorization of the given expresion is (2y+1)(4y-3a)

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