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EleoNora [17]
3 years ago
5

How many unique triangles can you construct with all sides having integers length, with one side of length 5 cm and a perimeter

less than or equal to 16 cm
Mathematics
1 answer:
Lisa [10]3 years ago
8 0
The answer is,
Only One.
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The first five terms of an arithmetic sequence are shown below: 20, 17, 14, 11, 8, . . . let n represent the term number and f(n
VMariaS [17]
For starters, find the common change in the terms, in this case each goes down by 3. This lets you know you're gonna have a -3n in your equation as each term decreases by 3. Your equation should be in f(n)=c+rn form, with r being change in f(n), or -3 in this case. This gives you f(n)=c-3n. Now, solve for c, add 3n to both sides to get f(n)+3n=c. Plug in your n of 1 and f(n) of 20 to get c=20+3(1)=23. Plug in your c to your f(n) formula to get f(n)=23-3n as your f(n) function.
7 0
3 years ago
Read 2 more answers
Factor by grouping <br> 6x^2-12x+x-2<br> factor completely
Marianna [84]
Uh ye here you go stranger hoped this help

5 0
3 years ago
How is 2 hours and 30 minutes more than 10% of the day
matrenka [14]
In order to find what 10% of a day is:

A day is 24 hours long.

Divide 24 by 100, then multiply the answer by 10.

24/100=0.24
0.24*10=2.4

So, 10% of the day is 2.4 hours.

2 hours and 30 minutes can be written as a decimal as 2.5.

So, 2 hours and 30 minutes is slightly more than 10% of the day.
4 0
3 years ago
Thirty students bought pennants for the football game. Plain pennants cost $4 each and fancy ones cost $8 each. If the total bil
sammy [17]

Answer:

number o students bought pennants = 18

 number of student bought fancy ones=12

Step-by-step explanation:

Let x be the number o students bought pennants

and y be the number of student bought fancy ones

total 30 students

x+y= 30

y=30-x

Plain pennants cost $4 each and fancy ones cost $8 each.

4x+8y=168

Substitute 30-x for y in second equation

4x+8(30-x)=168

4x+240-8x=168

240-4x=168

Subtract 240 from both sides

-4x=-72

divide both sides by -4

x=18

y=30-x

y=30-18= 12

number o students bought pennants = 18

 number of student bought fancy ones=12

6 0
4 years ago
What is the greatest common factor of 42, 126, and 210 ?
son4ous [18]
Prime factors of 42:    2x7x3
prime factors of 126:  2x3x3x7
prime factors of 210:  7x3x5x2
now we multiply all the factors that they all have in common: 2x3x7 which is 42. So the highest common factor is 42
4 0
3 years ago
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