Plane A 520 feet vertical rise 40 feet/min
plane B 3800 feet vertical dip 120 feet per minute.
vertically the speeds are 40 feet / minute & 120 feet /minute.
120 + 40 = 160 feet per minute.
the distance between them = 3800 -520 =3280 feet
t= d/r
3280/160
t = 20.5 minutes. they will be at the same altitude.
Answer:
-5
Step-by-step explanation:
Answer:
x=50
Step-by-step explanation:
40+65+25+x=180
Combine like terms
130+x=180
x=50
(triangles = 180)
Answer:
z = 21 ; y= 16
Step-by-step explanation:
first of all we have to isolate a variable.
In second expression we can obtain:
3y = 2z+6
y = 2/3 z + 2
now we have to substitute this value in the first equation and solve it
8(2/3z+2)-5z = 23
16/3z + 16 -5z = 23
16z +48 - 15z = 69
z = 21
now we have to substitute z in the second equation:
y = 2/3 (21) +2
y = 14+ 2 = 16
y = 16