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3 years ago

Compare A and B with greater or less signs, if: 50% of A is equal to $0.5a and 20% of B is equal to $0.2a

2 answers:

6 0

We have that
50% of A is equal to $0.5a
0.50A=0.5a----------> A=a

and
20% of B is equal to $0.2a
0.20B=0.2a---------> B=a

so
A=B

the answer is
A=B

bogdanovich [222]3 years ago

5 0

Answer:

a=b

Step-by-step explanation:

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help me pls I'll give brainliest to the person with the correct answer Which figure can be formed from the next

Sauron [17]

Answer:

The bottom one on the left

Step-by-step explanation:

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2 years ago

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You're in charge of evening entertainment for an important client group. You use the company credit card to take their four repr

svlad2 [7]

SOLUTION:

Tip = Total cost of dinner × 20%

Tip = [ 2 ( 32.5 ) + 2 ( 28.9 ) + 24.95 ] × 20%

Tip = [ 65 + 57.8 + 24.95 ] × 20%

Tip = [ 147.75 ] × 20%

Tip = $29.55

Therefore, the amount of tip you leave is $29.55.

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4 0

3 years ago

yulyashka [42]

Answer:

2x -5

Step-by-step explanation:

-3 + 2(x - 1)

Distribute

-3 +2x -2

Combine like terms

2x -5

3 0

3 years ago

Verify in the following whether g(x) is a factor of p(x)

notsponge [240]

$\red{\large\underline{\sf{Solution-i}}}$

Given that,

$\rm \longmapsto\: p(x) = {x}^{4} - {x}^{3} - {x}^{2} - x - 2$

and

$\rm \longmapsto\:g(x) = x - 2$

We know,

Factor theorem states that if g(x) = x - a is a factor of polynomial f(x), then remainder f(a) = 0.

So, using Factor theorem, Consider

$\rm \longmapsto\:p(2)$

$\rm \: = \: {2}^{4} - {2}^{3} - {2}^{2} - 2 - 2$

$\rm \: = \: 16 - 8 - 4 - 4$

$\rm \: = \: 16 - (8 + 4 + 4)$

$\rm \: = \: 16 - 16$

$\rm \: = \: 0$

$\rm\implies \:p(2) \: = \: 0$

So, 

$\bf\implies \:g(x) \: is \: factor \: of \: p(x)$

$\red{\large\underline{\sf{Solution-ii}}}$

$\rm \longmapsto\: p(x) = 2{x}^{3} + {x}^{2} - 2x + 1$

and

$\rm :\longmapsto\: g(x) = x + 1$

Now, By using Factor Theorem, Consider

$\rm \longmapsto\:p( - 1)$

$\rm \: = \: 2 {( - 1)}^{3} + {( - 1)}^{2} - 2( - 1) + 1$

$\rm \: = \: - 2 + 1 + 2 + 1$

$\rm \: = \: 2$

$\rm\implies \:p( - 1) \: \ne \: 0$

So, 

$\bf\implies \:g(x) \: is \: not \: a\: factor \: of \: p(x)$

8 0

3 years ago

*(The bottom part is x as it approaches infinity)*

Bess [88]

$\bf \lim\limits_{x\to \infty}~\left( \cfrac{1}{8} \right)^x\implies \lim\limits_{x\to \infty}~\cfrac{1^x}{8^x}\\\\[-0.35em] ~\dotfill\\\\ \stackrel{x = 10}{\cfrac{1^{10}}{8^{10}}}\implies \cfrac{1}{8^{10}}~~,~~ \stackrel{x = 1000}{\cfrac{1^{1000}}{8^{1000}}}\implies \cfrac{1}{8^{1000}}~~,~~ \stackrel{x = 100000000}{\cfrac{1^{100000000}}{8^{100000000}}}\implies \cfrac{1}{8^{100000000}}~~,~~ ...$

now, if we look at the values as "x" races fast towards ∞, we can as you see above, use the values of 10, 1000, 100000000 and so on, as the value above oddly enough remains at 1, it could have been smaller but it's constantly 1 in this case, the value at the bottom is ever becoming a larger and larger denominator.

let's recall that the larger the denominator, the smaller the fraction, so the expression is ever going towards a tiny and tinier and really tinier fraction, a fraction that is ever approaching 0.

6 0

4 years ago