M=1/6yd solve for y???
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Answer:
98% confidence interval for the average age of all students is [24.302 , 25.698]
Step-by-step explanation:
We are given that a random sample of 36 students at a community college showed an average age of 25 years.
Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.
So, the pivotal quantity for 98% confidence interval for the average age is given by;
P.Q. = ~ N(0,1)
where, = sample average age = 25 years
= population standard deviation = 1.8 years
n = sample of students = 36
= population average age
So, 98% confidence interval for the average age, is ;
P(-2.3263 < N(0,1) < 2.3263) = 0.98
P(-2.3263 < < 2.3263) = 0.98
P( <
<
) = 0.98
P( <
<
) = 0.98
98% confidence interval for = [
,
]
= [ ,
]
= [24.302 , 25.698]
Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].
For any right triangle, we can use the Pythagorean Theorem. The Pythagorean Theorem states that for any right triangle, the legs when squared and added together will be equal to the hypotenuse squared.
In mathematical notation:
Where the variables a and b are the legs and the variable c is the hypotenuse.
Because we know the two side lengths of the triangle, we can solve for the unknown side.
We know the length of one of the legs and the hypotenuse.
Plug in the values.
So, the square root of 476 is the unknown length.
In mathematical notation:
Where the variables a and b are the legs and the variable c is the hypotenuse.
Because we know the two side lengths of the triangle, we can solve for the unknown side.
We know the length of one of the legs and the hypotenuse.
Plug in the values.
So, the square root of 476 is the unknown length.