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3 years ago

Triangle XYZ is reflected about the y-axis What are the coordinates of X’?

Mathematics

1 answer:

son4ous [18]3 years ago

3 0

Answer:

We need more details to this question.

Step-by-step explanation:

You might be interested in

Can someone help me plss

77julia77 [94]

Answer:

Given, x = 2 and z = 12

z + 5x³

12 + 5×2³

12 + 5×8

12 + 40

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6 0

3 years ago

A students' choir contains 25 children and only 5 of them play the piano. If a child is selected at random, what is the probabil

solniwko [45]

Answer:

probability that the child DOES NOT play the piano

$P(E^{-}) =\frac{4}{5}$

Step-by-step explanation:

A students' choir contains 25 children

n(S) =25

The number of students play the piano =5

Let 'E' be the event of the child play the piano so n(E) =5

The probability of that the child play the piano

$P(E) = \frac{n(E)}{n(S)}$

$P(E) = \frac{5}{25}= \frac{1}{5}$

Let 'E⁻ be the event of the child play does not play the piano

$P(E^{-}) = 1- P(E)$

$P(E^{-}) = 1- \frac{1}{5} =\frac{4}{5}$

<u>Conclusion</u>:-

probability that the child DOES NOT play the piano

$P(E^{-}) =\frac{4}{5}$

5 0

4 years ago

An electronics company produces transistors, resistors, and computer chips. Each transistor requires 3 units of copper, 2 unit

Gala2k [10]

Answer:

475 transistors, 25 resistors and 50 computer chips can be produced.

Step-by-step explanation:

Let us consider, p = Number of transistors.

q = Number of resistors.

r = Number of computer chips.

The following three linear equations according to question,

$3\times p + 3\times q + 2\times r = 1600\\2\times p + 1\times q + 1\times r = 1025\\1\times p + 2\times q + 2\times r = 625$

The matrix form of any system, Ax = B

Where, A = Coefficient matrix

B = Constant vector

x = Variable vector

$A = \left[\begin{array}{ccc}3&3&2\\2&1&1\\1&2&2\end{array}\right], x = \left[\begin{array}{ccc}p\\q\\r\end{array}\right], B = \left[\begin{array}{ccc}1600\\1025\\625\end{array}\right]$

The inverse matrix, $A^{-1}$ can be found by using the following formula,

$A^{-1} = \frac{1}{det A}\times (C_{A}) ^{T}$

Where, det A = Determinant of matrix A.

$C_{A}$ = Matrix of cofactors of A

Now, applying this formula to find $A^{-1}$ ;

$det A = \left[\begin{array}{ccc}3&3&2\\2&1&1\\1&2&2\end{array}\right] = 3\times(2-2)-3\times(4-1)+2\times(4-1) = -3$

Here, $det A\neq 0$ , thus the matrix is invertible.

$C_{A} = \left[\begin{array}{ccc}(2-2)&-(4-1)&(4-1)\\-(6-4)&(6-2)&-(6-3)\\(3-2)&-(3-4)&(3-6)\end{array}\right] = \left[\begin{array}{ccc}0&-3&3\\-2&4&-3\\1&1&-3\end{array}\right] \\(C_{A}) ^{T} = \left[\begin{array}{ccc}0&-3&3\\-2&4&-3\\1&1&-3\end{array}\right] ^{T} = \left[\begin{array}{ccc}0&-2&1\\-3&4&1\\3&-3&-3\end{array}\right]$

$A^{-1} = \frac{1}{-3}\times\left[\begin{array}{ccc}0&-2&1\\-3&4&1\\3&-3&-3\end{array}\right] \\ So, x= \frac{1}{-3} \left[\begin{array}{ccc}0&-2&1\\-3&4&1\\3&-3&-3\end{array}\right]\times\left[\begin{array}{ccc}1600\\1025\\625\end{array}\right]= \frac{1}{-3} \left[\begin{array}{ccc}-1425\\-75\\-150\end{array}\right] = \left[\begin{array}{ccc}475\\25\\50\end{array}\right]$