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Anni [7]
3 years ago
14

The Earp vitamin company offers a list price of $0.02 per unit. If you order 4,000 units and receive a discount rate of 15 perce

nt, your net price would be
Mathematics
1 answer:
Virty [35]3 years ago
4 0
$68 net price

$.02 x 4000 units= $80
$80 x 15% (discount) = $12 discount
$80- $12 = $68 net price
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An architect is designing a gym for a new elementary
Liono4ka [1.6K]

Answer:

60

Step-by-step explanation: 60x116=6960

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3 years ago
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5) Mrs. Bell went bowling again. Her bowling scores were 100, 172, 85, and 92. She wants
Alex73 [517]

Answer: She needs to bowl 120 or more on her next game.

Step-by-step explanation:

8 0
3 years ago
A school dance committee has 14 volunteers. Each dance requires 3 volunteers at the door, 5 volunteers on the floor, and 6 float
siniylev [52]

There are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned from 14 volunteers.

Given that a school dance committee has 14 volunteers and each dance requires 3 volunteers at the door, 5 volunteers on the floor and 6 on floaters.

We are required to find the number of ways in which the volunteers can be assigned.

Combinations means finding the ways in which the things can be choosed to make a new thing or to do something else.

nC_{r}=n!/r!(n-r)!

Number of ways in which the volunteers can be assigned is equal to the following:

Since 2 have not been assigned so left over volunteers are 14-2=12 volunteers.

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=14!/12!(14-12)!

=14!/12!*2!

=14*13/2*1

=91 ways

Hence there are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned.

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5 0
2 years ago
stion 1 OT 5A researcher recorded the number of swans and the number of ducks in a lake every month. Function s represents the n
Anon25 [30]

Given functions are

s(n)=2(1.1)^n+5_{}d(n)=4(1.08)^n+3

The total number of ducks and swans in the lake after n months can be determined by adding the functions s(n) and d(n).

t(n)=s(n)+d(n)

t(n)=(2(1.1)^n^{}+5)+(4(1.08)^n+3)

t(n)=2(1.1)^n+5+4(1.08)^n+3

t(n)=2(1.1)^n+4(1.08)^n+5+3

t(n)=2(1.1)^n+4(1.08)^n+8

Taking 2 as common, we get

t(n)=2\lbrack(1.1)^n+2(1.08)^n+4\rbrack

Hence The total number of ducks and swans in the lake after n months is

t(n)=2\lbrack(1.1)^n+2(1.08)^n+4\rbrack

8 0
1 year ago
Helpppppppppppppppppppppppppp
Dahasolnce [82]

Step-by-step explanation:

2\pi {r}^{2}  + 2\pi  rh

2(3.14) {(20)}^{2}  + 2(3.14)(20)(11)

6.28(400) + 6.28(220) \\ 2512 + 1381.6 = 3893.6 {mi}^{2}

3 0
3 years ago
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