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Goshia [24]
3 years ago
8

I need help getting the answer please

Mathematics
1 answer:
____ [38]3 years ago
6 0
This is the answer
\frac{21}{1}   \div  \frac{3}{4}    =  \frac{21}{1}  \times  \frac{4}{3} \\  =  \frac{84}{3}   = 28
or you can solve it like this
21 \div  \frac{3}{4}  = 21 \div 0.75 = 28
hope this helps
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Recall that a relation is an <em>equivalence relation</em> if and only if is symmetric, reflexive and transitive. In order to simplify the notation we will use A↔B when A is in relation with B.

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<em>Symmetric</em>: We need to prove that A↔B implies B↔A. As A↔B there exists an invertible matrix P such that A=P^{-1}BP. In this equality we can perform a right multiplication by P^{-1} and obtain AP^{-1} =P^{-1}B. Then, in the obtained equality we perform a left multiplication by P and get PAP^{-1} =B. If we write Q=P^{-1} and Q^{-1} = P we have B = Q^{-1}AQ. Thus, B↔A.

<em>Transitive</em>: We need to prove that A↔B and B↔C implies A↔C. From the fact A↔B we have A=P^{-1}BP and from B↔C we have B=Q^{-1}CQ. Now, if we substitute the last equality into the first one we get

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the answer to the expression is u=4

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