Let the amount deposited (principal) be x, then the amount after the required time = 2x.
A = P(1 + r/n)^nt: where A is the future value = 2x, P is the principal = x, r is the rate = 0.75%, n is the number of accumulation in a year = 12, t is the number of years.
2x = x(1 + 0.0075/12)^12t
2 = (1 + 0.000625)^12t
log 2 = 12t log (1.000625)
log 2 / log (1.000625) = 12t
1109.38 = 12t
t = 92 years
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Answer:
PQ and QR are congruent.
Step-by-step explanation:
The length of PQ = sqrt [(2 - -1)^2 + (-1 - 3)^2]
= sqrt 25
= 5 units.
QR = sqrt [(5-2)^2 + (3 - -1)^2) ]
= sqrt 25
= 5 units.
PR = sqrt [ ( 3-3^2 + (5- -1)^2]
= sqrt 36
= 6 units.
Based on the simple interest amount he could be making, and the rate of investment, Tyrell's additional interest per month is $1,000.
<h3>How much is Tyrell paying in additional interest?</h3>
Assuming the additional interest that Tyrell is paying is x, the following formula can be used:
300 = (x × 2.5%) x 12 months
Solving gives:
300 = 0.025x × 12
0.025x = 300/12
x = 25 / 0.025
x = $1,000
Find out more on additional interest at brainly.com/question/27037531.
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If you round it to the nearest pound it is 1.1 kg
2.5/2.2 = 1.13....