You need to make the right side = 0
To do this you subtract 10 from both sides of the equation:-
x^2 + 6x + 9 - 10 = 10 - 10
x^2 + 6x - 1 = 0
Answer:
See Explanation
Step-by-step explanation:
The question is incomplete, as the required lengths are not given.
I will use the following data set to answer the question.

First, is to determine the range of the dataset



Next, we will make use of 4 classes. So, we divide range by 10 to get the number of class. 10 represents the interval




<em>So, we use 4 classes</em>
Plot the frequency distribution table as follows:

<em>See attachment for histogram</em>
Answer:
a. see attached
b. H(t) = 12 -10cos(πt/10)
c. H(16) ≈ 8.91 m
Step-by-step explanation:
<h3>a.</h3>
The cosine function has its extreme (positive) value when its argument is 0, so we like to use that function for circular motion problems that have an extreme value at t=0. The midline of the function needs to be adjusted upward from 0 to a value that is 2 m more than the 10 m radius. The amplitude of the function will be the 10 m radius. The period of the function is 20 seconds, so the cosine function will be scaled so that one full period is completed at t=20. That is, the argument of the cosine will be 2π(t/20) = πt/10.
The function describing the height will be ...
H(t) = 12 -10cos(πt/10)
The graph of it is attached.
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<h3>b. </h3>
See part a.
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<h3>c.</h3>
The wheel will reach the top of its travel after 1/2 of its period, or t=10. Then 6 seconds later is t=16.
H(16) = 12 -10cos(π(16/10) = 12 -10cos(1.6π) ≈ 12 -10(0.309017) ≈ 8.90983
The height of the rider 6 seconds after passing the top will be about 8.91 m.
1. U wrote wrong no answer possible from list
2. 90
D is the closes answer I can think of. It forms an equilateral triangle, that has points equal distance from each other