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Sholpan [36]
3 years ago
5

luke jogged a total of 56.5 miles last week. if luke jogged the same distance,d, each day for 3 days and half that distance on e

ach of the reamaining days, which algebraic equation can he use to determine how many miles he jogged each day
Mathematics
1 answer:
Leokris [45]3 years ago
3 0
The algebraic equation used to answer this question is:
3d + 4(1/2d) = 56.5
This is because he ran d, the distance, three times that week. For the rest of the four days, he ran 1/2 the distance, or half d.
To find the answer, you first distribute:
3d + 2d = 56.5
Add like terms:
5d = 56.5
Divide both side by 5:
5d/5 = 56.5/5
d = 11.3
On the first three days, Luke jogged 11.3 miles. On the remaining days, where he jogged 1/2d, Luke jogged 5.65 miles.
Hope this helps!
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Answer:  The answer is 12.

Step-by-step explanation: Given that a point 'x' is lying at \dfrac{2}{3} on the number line. Another point 'y' is also lying at the same distance from 0 but has a numerator of 8. We are to find the denominator of 'y'.

Since 'x' is lying at \dfrac{2}{3} on the number line so its distance from 0 will be

d_x=\dfrac{2}{3}-0=\dfrac{2}{3}.

Let the denominator of 'y' be p, then its distance from 0 will be

d_y=\dfrac{8}{p}-0=\dfrac{8}{p}.

According to the given information, we must have

d_x=d_y\\\\\\\Rightarrow \dfrac{2}{3}=\dfrac{8}{p}\\\\\\\Rightarrow p=\dfrac{8\times 3}{2}=12.

Thus, the denominator will be 12.

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3 years ago
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Step-by-step explanation:

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Elena-2011 [213]

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Allushta [10]

Step-by-step explanation:

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