Answer:
total population of school = 1000
1000 - 450 males = 550 female students
550 - 200 females not in extra curriculars = 350 females in extra curriculars
350 + 90 males in extra curriculars = 440 total in extra curriculars
Circle A = 440
Circle B - overlap = 200 females not in extra curriculars
440 + 200 = 640
1000 - 640 = 370 students represented by the portion of the Venn diagram not in either circle
Step-by-step explanation:
Answer:
The rectangle's area is 48 square meters
Step-by-step explanation:
Recall that the perimeter of a rectangle of base b and height h is given by the formula:
Perimeter = 2 b + 2 h
we know that the perimeter is 28 meters, then we can create our first equation;
2 b + 2 h = 28
which means:
2 (b + h) = 28
b + h = 28/2
b + h = 14
the tell us that the diagonal is 10 meters, so we use the Pythagorean theorem to write a second equation using the rectangle's base, height, and diagonal (which form in between the three a right angle triangle where the hypotenuse is the rectangle's diagonal:
So, we can use the equation : b + h = 14 to write one variable in terms of the other one and use it as substitution in the second (quadratic) equation:
h = 14 - b
then:
which we have reduced at the end by dividing both sides by 2.
we can use factoring to solve these equation;
Se we find two possible solutions: b = 6 m or b = 8 m
If we call b = 8 m, then the height becomes h = 14 - (8) = 6 m
and viceversa.
So a rectangle with such dimensions will render an area that equals :
Area = b x h = 8 x 6 = 48 square meters.
<h2>B.
0</h2>
The highest point the curves reach is 0.
An equation between two variables that gives a straight line when plotted on a graph.
Answer:
w = -20
Step-by-step explanation:
Solve for w:
4 - 2 (1 - w) = -38
Hint: | Distribute -2 over 1 - w.
-2 (1 - w) = 2 w - 2:
2 w - 2 + 4 = -38
Hint: | Group like terms in 2 w - 2 + 4.
Grouping like terms, 2 w - 2 + 4 = 2 w + (4 - 2):
2 w + (4 - 2) = -38
Hint: | Evaluate 4 - 2.
4 - 2 = 2:
2 w + 2 = -38
Hint: | Isolate terms with w to the left hand side.
Subtract 2 from both sides:
2 w + (2 - 2) = -2 - 38
Hint: | Look for the difference of two identical terms.
2 - 2 = 0:
2 w = -2 - 38
Hint: | Evaluate -2 - 38.
-2 - 38 = -40:
2 w = -40
Hint: | Divide both sides by a constant to simplify the equation.
Divide both sides of 2 w = -40 by 2:
(2 w)/2 = (-40)/2
Hint: | Any nonzero number divided by itself is one.
2/2 = 1:
w = (-40)/2
Hint: | Reduce (-40)/2 to lowest terms. Start by finding the GCD of -40 and 2.
The gcd of -40 and 2 is 2, so (-40)/2 = (2 (-20))/(2×1) = 2/2×-20 = -20:
Answer: w = -20