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Furkat [3]
3 years ago
11

what is the equation in standard form of the line that passes through the point (4,-8) and has a slope of 1/4

Mathematics
1 answer:
Sergio039 [100]3 years ago
6 0
Y = mx + b
slope(m) = 1/4
(4,-8)....x = 4 and y = -8
now sub and find b, the y int
-8 = 1/4(4) + b
-8 = 1 + b
-8 - 1 = b
-9 = b
so ur equation is : y = 1/4x - 9....but we need it in standard form

y = 1/4x - 9
-1/4x + y = -9...multiply everything by -4
x - 4y = 36 <====
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m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = B(- 4, 2) and (x₂, y₂ ) = C(- 2, - 2)

m = \frac{-2-2}{-2+4} = \frac{-4}{2} = - 2

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To find c substitute either of the 2 points into the partial equation

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2x + y = -4<br> 2x + 3y = 4
kirill115 [55]

Answer: x=4 ; y=<u> -4</u>

                            3

Step-by-step explanation:

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    4

x=4

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   3

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