3 years ago

PLEASE HELP WILL GIVE BRAINLIEST TO CORRECT ANSWER

2 answers:

7 0

So the way to determine is to find the density of your unknown metal. To do that, you know density is g/mL or g/cm3. So, you do 979/58. It is approximately 16.88 g/mL. So, the density is more than pure gold. (A)

I’m not 100% sure that mL = cm3 for this case so make sure you check that but that’s what I think the answer is!

wel3 years ago

4 0

Answer:

C. Yes, the density equals that of pure silver (10.5)

Step-by-step explanation:

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What is the average (arithmetic mean) of the first 90 measurements in a certain list of 92 measurements? (1) the average of the

marishachu [46]

The sum of all the measurements is just the average times the number.

$\bar x = \frac{1}{n} \sum_{i=1}^n x_i$

$\sum_{i=1}^n x_i = n \bar x$

So if the average of all 92 is 7 the sum of those is $92 \times 7$

The average of the last two is 7.2 so their sum is $2 \times 7.2$

That means the sum of the first 90 is $92 \times 7 - 2 \times 7.2$

so the average of the first 90 is

$\dfrac{92 \times 7 - 2 \times 7.2}{90} = 6.99556$ cm

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3 years ago

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Pachacha [2.7K]

Answer:

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Step-by-step explanation:

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