Ask question

Ask question

All categories

3 years ago

8

On a trip, the Olsons drove 165 miles in 3 hours. They keep the same average speed the whole trip. Which proportion can be used

to find the number of hours, H, it will take to travel 650 miles?
h/3=165/650
h/165=650/3
h/650=3/165
h/650 = 165/3

1 answer:

zheka24 [161]3 years ago

3 0

165/3=55 mph

650/55=h
650/(165/3)=h
(650*3)/165=h
3/165=h/650
h/650=3/165

so it is the third option

You might be interested in

Finding general term of sequence

kicyunya [14]

Notice that there's a pattern in the given sequence.

1, 4, 9, 16,............ can be written as 1², 2², 3², 4²,...............

So, the general term of the given sequence is y_{n}=(n)^{2}

5 0

3 years ago

In 2017, there were about 21 million teenagers (aged 13-17) in the United States. They each

vivado [14]

The Number of text messages sent in a month is 1.68 × $10^{(-8)}$

Step-by-step explanation:

Step 1 :

Total number of teenagers in United States = 21 million

Average text messages sent per month = 800

We need to find the number of text messages sent each month

Step 2 :

The number of text messages in a month can be computed by taking the product of the total number of teenagers and average messages sent per month

Therefore

Number of text messages that is sent in a month = 21 million × 800

= 21 × $10^{6}$ × 800

= 168 × $10^{6}$ = 1.68 × $10^{(-8)}$

Step 3 :

Answer :

The Number of text messages that is sent in a month is 1.68 × $10^{(-8)}$

5 0

2 years ago

Write the prime factorization of 138

Natali [406]

Answer:

138 ÷ 2 = 69

69 ÷ 2 = 34.5

69 ÷ 3 = 23

23 ÷ 3 = 7.67

23 ÷ 5 = 4.6

23 ÷ 7 = 3.2857

23 ÷ 11 = 2.0909

-----------------------

23 ÷ 23 = 1

7 0

2 years ago

2 times 4? Will mark brainliest! 100 p

fomenos

Answer:

6

Step-by-step explanation:

7 0

2 years ago

Identify the initial amount a and the decay factor b in the exponential function. y equals 5 times 0.5 superscript x

Ber [7]

$\bf \qquad \textit{Amount for Exponential Decay}
\\\\
A=a(b)^x\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
a=\textit{initial amount}\\
b=\textit{decay factor}\\
x=\textit{elapsed time}\\
\end{cases}
\\\\\\
y=\stackrel{a}{5}(\stackrel{b}{0.5})^x$

7 0

2 years ago