Question

(05.01 MC)

Answer 1

Answer:

The correct option is C. The value of y be on the graph than is 60 more than the y value in the table when x = 12.

Step-by-step explanation:

If a line passing through two points then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

From the given table it is clear that the line passing thought the points (4,100) and (5,125).

$y-100=\frac{125-100}{5-4}(x-4)$

$y-100=25(x-4)$

$y-100=25x-100$

$y=25x$

The value of this function at x=12 is

$y=25(12)=300$

From the given table it is clear that the line passing thought the points (0,0) and (2,60).

$y-0=\frac{60-0}{2-0}(x-0)$

$y=30x$

The value of this function at x=12 is

$y=30(12)=360$

The difference between y value in the graph and in the table at x=12 is

$360-300=60$

The value of y be on the graph than is 60 more than the y value in the table when x = 12. Therefore the correct option is C.

Answer 2

For the table, y = 25x.
When x = 12, y = 25*12 = 300

For the graph, y = 30x
When x = 12, y = 30*12 = 360

When x = 12, the value of y on the graph is 60 more than its value in the table.