All categories

3 years ago

Which doubles fact helps you solve 5+6=11? Circle the number sentence.

Mathematics

1 answer:

Iteru [2.4K]3 years ago

6 0

Answer:

5 + 5 = 10

Step-by-step explanation:

If you know that 5 + 5 = 10, you can solve 5 + 6 = 11. You are adding one more to the addends (adding 6 instead of adding 5), so you add one more to the sum (11 instead of 10).

You might be interested in

Pls help I need it by 11:59

chubhunter [2.5K]

no se por que veo esto jaja

8 0

3 years ago

Solve the system of equations. Show your work.<br> y = x^2 -3x +4 <br> x + y = 4

sesenic [268]

Answer:

x + y = 2 , y = x 2 − 4 x + 4

Replace all occurrences of

with x 2 − 4 x + 4

in each equation.

x 2 − 3 x + 4 = 2 y = x 2 − 4 x + 4

Solve for

in the first equation.

x = 2 , 1 y = x 2 − 4 x+ 4

Replace all occurrences of

x with 2

in each equation.

y=0 x = 2

Replace all occurrences of x

with 1

in each equation.

y = 1 x = 1

The solution to the system is the complete set of ordered pairs that are valid solutions.

( 2 , 0 ) ( 1 , 1 )

The result can be shown in multiple forms.

Point Form:

( 2 , 0 ) , ( 1 , 1 )

Equation Form:

x=2 , y = 0 x = 1 , y = 1

Step-by-step explanation:

3 0

3 years ago

A bird was sitting 5 feet from the base of an oak tree and flew 13 feet to reach the top of the tree. How tall is the tree?

Citrus2011 [14]

Answer:

The tree is 18 feet high.

Step-by-step explanation:

The base was 5 feet away. The bird flew an additional 13 feet.

5+13=18.

5 0

3 years ago

Y″+ 5y′ + 6y = 3δ(t − 2) − 4δ(t −5); y(0) = y′′(0) = 0

Snowcat [4.5K]

Answer:

y(t) = 3u₂(t) [ $e^{-2t+4} - e^{-5t + 10)}$ ] - 4u₅(t) [ $e^{-2t+10)} - e^{-5t + 25)}$ ]

Step-by-step explanation:

To find - y″+ 5y′ + 6y = 3δ(t − 2) − 4δ(t −5); y(0) = y′(0) = 0

Formula used -

L{δ(t − c)} = $e^{-cs}$

L{f''(t) = s²F(s) - sf(0) - f'(0)

L{f'(t) = sF(s) - f(0)

Solution -

By Applying Laplace transform, we get

L{y″+ 5y′ + 6y} = L{3δ(t − 2) − 4δ(t −5)}

⇒L{y''} + 5L{y'} + 6L{y} = 3L{δ(t − 2)} − 4L{δ(t −5)}

⇒s²Y(s) - sy(0) - y'(0) + 5[sY(s) - y(0)] + 6Y(s) = 3 $e^{-2s}$ - 4 $e^{-5s}$

⇒s²Y(s) - 0 - 0 + 5[sY(s) - 0] + 6Y(s) = 3 $e^{-2s}$ - 4 $e^{-5s}$

⇒s²Y(s) + 5sY(s) + 6Y(s) = 3 $e^{-2s}$ - 4 $e^{-5s}$

⇒[s² + 5s + 6] Y(s) = 3 $e^{-2s}$ - 4 $e^{-5s}$

⇒[s² + 3s + 2s + 6] Y(s) = 3 $e^{-2s}$ - 4 $e^{-5s}$

⇒[s(s + 3) + 2(s + 3)] Y(s) = 3 $e^{-2s}$ - 4 $e^{-5s}$

⇒[(s + 2)(s + 3)] Y(s) = 3 $e^{-2s}$ - 4 $e^{-5s}$

⇒Y(s) = $\frac{3e^{-2s} }{(s + 2)(s + 3)} - \frac{4e^{-5s} }{(s + 2)(s + 3)}$

Now,

Let

$\frac{1}{(s+2)(s+3)} = \frac{A}{s+2} + \frac{B}{s+3} \\\frac{1}{(s+2)(s+3)} = \frac{A(s + 3) + B(s+2)}{(s+2)(s+3)}\\1 = As + 3A + Bs + 2B\\1 = (A+B)s + (3A + 2B)$

By Comparing, we get

A + B = 0 and 3A + 2B = 1

⇒A = -B

and

3(-B) + 2B = 1

⇒-B = 1

⇒B = -1

So,

A = 1

∴ we get

$\frac{1}{(s+2)(s+3)} = \frac{1}{s+2} + \frac{-1}{s+3}$

So,

Y(s) = $3e^{-2s}[ \frac{1}{(s + 2)} - \frac{1}{(s + 3)}] - 4e^{-5s}[ \frac{1}{(s + 2)} - \frac{1}{(s + 3)}]$

⇒Y(s) = $3e^{-2s} \frac{1}{(s + 2)} - 3e^{-2s} \frac{1}{(s + 3)} - 4e^{-5s}\frac{1}{(s + 2)} + 4e^{-5s}\frac{1}{(s + 3)}$

By applying inverse Laplace , we get

y(t) = 3u₂(t) [ $e^{-2(t-2)} - e^{-5(t - 2)}$ ] - 4u₅(t) [ $e^{-2(t-5)} - e^{-5(t - 5)}$ ]

⇒y(t) = 3u₂(t) [ $e^{-2t+4} - e^{-5t + 10)}$ ] - 4u₅(t) [ $e^{-2t+10)} - e^{-5t + 25)}$ ]

It is the required solution.

3 0

3 years ago

What were the key arguments of the Magna Carta? <br> Plz help

alisha [4.7K]

Answer:

Magna Carta, which means 'The Great Charter', is one of the most important documents in history as it established the principle that everyone is subject to the law, even the king, and guarantees the rights of individuals, the right to justice and the right to a fair trial.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers