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V125BC [204]
3 years ago
5

You need to prepare 30mL solution of a 1:8 syrup solution. You have on hand 50% syrup solution and a 1:20 soda solution. How man

y mL of each solution do you need to create the final solution?
Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
8 0

Answer:

5 ml of 50% syrup solution will be used to create the final solution

Step by step Explanation:

Let the amount of 50% solution that was used = b

Which means ( 30 - b ) is the amount of 1/200 solution used then we can derive an equation as follows,

set up will then be,

0.5b +0.05(30 -b) = 1/8 (30)

We can simplifiy this as

0.5b+ 1.5 -0.05b = 3.75

Then make b the subject of the formula we have

0.45b = 2.25

b= 2.25/0.45

b = 5 ml

Therefore, 5ml of 50% syrup solution will be used to create the final solution

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Which mathematical sentence most Accurately expresses the information in the problem below?
d1i1m1o1n [39]

Answer:

Don't quote me on this but it's probably C. 12c ≥ 88

Step-by-step explanation:

This is because he packages 88 eggs <em>into </em>cartons of 12.

88/12 is 7.33333... so it makes sense to have a greater or equal amount of eggs. If you multiply 7.333333... by 12, each additional 3 gets you closer to 88 so again, makes sense to have more.

5 0
2 years ago
Anyone want 98 points? Answer and explain the answer below.
Brums [2.3K]

It will be easier to understand this using a venn diagram :


































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3 years ago
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Which answer best describes the complex zeros of the polynomial function?
marysya [2.9K]

<u>Answer-</u>

<em>D. The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location.</em>

<u>Solution-</u>

The given polynomial is,

f(x)=x^3-x^2+6x-6

The zeros of the polynomials are,

\Rightarrow f(x)=0

\Rightarrow x^3-x^2+6x-6=0

\Rightarrow x^2(x-1)+6(x-1)=0

\Rightarrow (x^2+6)(x-1)=0

\Rightarrow (x^2+6)=0,(x-1)=0

\Rightarrow x=\sqrt{-6},\ x=1

\Rightarrow x=1,\ \pm \sqrt6i

Therefore, this function has only one real zero i.e 1 and two nonreal zeros i.e ±√6i . The graph of the function intersects the x-axis at exactly one location i.e at x = 1

3 0
3 years ago
Si un triángulo tiene una hipotenusa de 15 cm y un cateto que mide 12 cm, ¿cual es la longitud del otro cateto?
BartSMP [9]

Answer:

   

9cm

Explicación:

El teorema de pitagoras nos dice que la hipotenusa al cuadrado es igual a la suma de los catetos al cuadrado:

c^{2} =a^{2} + b^{2}

Donde c es la hipotenusa y a  y b son los catetos.

Por lo cual, podemos reemplazar c por 15cm y a por 12cm :

15^{2} =12^{2} +b^{2}

Finalmente , debemos resolver la ecuación para b, así que b es igual a :

225=144+b^{2} \\225-144=144+b^{2} -144\\81=b^{2} \\\sqrt{81} =b\\9=b

Por lo tanto, la longitud del otro cateto es 9 cm

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2 years ago
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This simplifies to the square root of -12^2+5^2, or the square root of 144+25.

144+25=169.

the square root of 169 is 13

4 0
3 years ago
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