HELP FAST!!!! -5=-2/3x +3
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Slope-intercept form: y = mx + b
[m is the slope, b is the y-intercept or the y value when x = 0 ---> (0, y) or the point where the line crosses through the y-axis]
To find the slope, you use the slope formula:
And plug in the two points
(-6, 2) = (x₁ , y₁)
(1, 16) = (x₂ , y₂)
[two negatives cancel each other out and become positive]
m = 2 Now that you found m, plug it into the equation
y = mx + b
y = 2x + b To find b, plug in one of the points into the equation
(-6, 2)
y = 2x + b
2 = 2(-6) + b
2 = -12 + b Add 12 on both sides
14 = b
(1, 16)
y = 2x + b
16 = 2(1) + b Subtract 2 on both sides
14 = b
Now that you found b, plug it into the equation
y = 2x + 14
The domain is the set of allowed input x values for the function. In this case, the domain is the inequality x > -8 (note the vertical asymptote at x = -8 in which the function never touches)
If you want to write the domain in interval notation, then you would write
which is the interval from -8 to positive infinity (excluding both endpoints)
If you want to write the domain in interval notation, then you would write