Question

Please solve this for me. Thanks

Answer 1

Answer:

10y = 13x + 139

Step-by-step explanation:

Points (-5, -3) and (-15, -16) are the two points through which Line 1 passes.

So, the slope of the line 1 is $\frac{-3-(-16)}{-5-(-15)} =\frac{13}{10}$

Now, the slope of the parallel straight line i.e. line 2 will be same as line 1 i.e. $\frac{13}{10}$

Let us assume that the equation of line 2 is

$y= \frac{13}{10} x+c$ {Where c is a constant} ....... (1)

Now, line 2 passes through the point (-13, 17). Hence, this point will satisfy equation (1).

So,  $17= \frac{13}{10} (-13)+c$

⇒ $c=\frac{139}{10}$

Therefore, the equation of line 2 will be

$y=\frac{13}{10} x+\frac{139}{10}$

⇒ 10y = 13x + 139  (Answer)