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djverab [1.8K]
3 years ago
11

What is the quotient of -8a^8b^-2/10a^-4b^-10 in simplified form? Assume a=0 b=0 A.) -4a^12b^8/5 B.)-4a^32b^5/5 C.)a^12b^8/80 D.

)a^32b^5/80
Mathematics
2 answers:
Naily [24]3 years ago
4 0

-8a^8b^-2/10a^-4b^-10

= (-8/10) a^(8+4)b^(-2+10)

= -4/5 a^12 b^8

=-4 a^12 b^8 / 5

Answer is A.) -4 a^12 b^8 / 5

gogolik [260]3 years ago
4 0

Answer:

\frac{-4a^{12}b^8}{5}

Step-by-step explanation:

Write -8a^8b^-2/10a^-4b^-10 in simplified form

\frac{-8a^8b^{-2}}{10a^{-4}b^{-10}}

To simplify this we apply property of exponents

\frac{a^m}{a^n} = a^{m-n}

\frac{-8}{10} =-\frac{4}{5}

\frac{a^8}{a^{-4}} = a^{8-(-4)}=a^{12}

\frac{b^{-2}}{b^{-10}} = b^{-2-(-10)}=b^{8}

So simplified expression is

\frac{-4a^{12}b^8}{5}

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