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Luden [163]
3 years ago
9

A rectangle has a length of 11 inches and a width of 7 inches. If the length is increased by xx inches and the width increased b

y three times that amount, express the area of the rectangle as a function of x.
A(x)=??
Mathematics
1 answer:
charle [14.2K]3 years ago
8 0
A(x) = (11+x)(7+3x)
A(x) = 77 + 33x + 7x + 3x^2
A(x) = x^2 + 40x + 77

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Segment FG begins at point F(-2, 4) and ends at point G(-2, -3). The segment is translated 3 units left and 2 units up, then ref
Alexus [3.1K]

Answer:

F'G' = 7

Step-by-step explanation:

Given

F = (-2,4)

G = (-2,-3)

Required

Distance of F'G'

The transformation that give rise to F'G' from FG are:

  • Translation
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The above transformations are referred to as rigid transformation, and as such the side lengths remain unchanged.

i.e.

F'G' = FG

Calculating FG, we have:

FG = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}

Where:

F = (-2,4) --- (x_1,y_1)

G = (-2,-3) --- (x_2,y_2)

FG = \sqrt{(-2 - -2)^2 + (4 - -3)^2}

FG = \sqrt{(0)^2 + (7)^2}

FG = \sqrt{0 + 49}

FG = \sqrt{49}

Take positive square root

FG = 7

Recall that:

F'G' = FG

F'G' = 7

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Answer:

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Step-by-step explanation:

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To find the area of a triangle you multiply the base by the height and divide it by 2.

Example: 6 × 6 = 36

36 ÷ 2 = 18

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