Question

What is the hydrate formula for something that is 0.0248 mol Bal2 and 0.075 mol H20?

Answer 1

Answer: BaI {2} ⋅ 4 H {2} O

any number in {} is small

Explanation: The idea here is that you need to use the number of moles of anhydrous barium iodide,  BaI {2} , and of water,  H  {2}  O , to find the mole ratio that exists between the anhydrous salt and its water of hydration in the hydrate.