ANSWER
Find out the how long will the Yellow balloon be higher than the orange balloon.
To proof
Now the diagram is given below
As given
A yellow hot-air balloon is 100 feet off the ground and rising at rate of 8 feet per second.
i.e height of the yellow baloon off the ground = 100 feet
rising at rate = 8 feet per second.
.An orange hot-air balloon is 160 feet off the ground and rising at a rate of 5 feet per second.
i.e height of the orange baloon off the ground = 160 feet
rising at rate = 5feet per second.
Formula

Relative velocity = rising rate of yellow balloon - rising rate of orange balloon
= 8 -5
= 3 feet per second
Relative distance = height of the yellow baloon off the ground - height of the orange baloon off the ground
= 160 -100
= 60 feet
put in the formula

= 20 second
after 20 second Yellow balloon will be higher than the orange balloon.
Hence proved
The formula for the nth term of a geometric sequence:

a₁ - the first term, r - the common ratio
![54, a_2, a_3, 128 \\ \\ a_1=54 \\ a_4=128 \\ \\ a_n=a_1 \times r^{n-1} \\ a_4=a_1 \times r^3 \\ 128=54 \times r^3 \\ \frac{128}{54}=r^3 \\ \frac{128 \div 2}{54 \div 2}=r^3 \\ \frac{64}{27}=r^3 \\ \sqrt[3]{\frac{64}{27}}=\sqrt[3]{r^3} \\ \frac{\sqrt[3]{64}}{\sqrt[3]{27}}=r \\ r=\frac{4}{3}](https://tex.z-dn.net/?f=54%2C%20a_2%2C%20a_3%2C%20128%20%5C%5C%20%5C%5C%0Aa_1%3D54%20%5C%5C%0Aa_4%3D128%20%5C%5C%20%5C%5C%0Aa_n%3Da_1%20%5Ctimes%20r%5E%7Bn-1%7D%20%5C%5C%0Aa_4%3Da_1%20%5Ctimes%20r%5E3%20%5C%5C%0A128%3D54%20%5Ctimes%20r%5E3%20%5C%5C%0A%5Cfrac%7B128%7D%7B54%7D%3Dr%5E3%20%5C%5C%20%5Cfrac%7B128%20%5Cdiv%202%7D%7B54%20%5Cdiv%202%7D%3Dr%5E3%20%5C%5C%0A%5Cfrac%7B64%7D%7B27%7D%3Dr%5E3%20%5C%5C%0A%5Csqrt%5B3%5D%7B%5Cfrac%7B64%7D%7B27%7D%7D%3D%5Csqrt%5B3%5D%7Br%5E3%7D%20%5C%5C%0A%5Cfrac%7B%5Csqrt%5B3%5D%7B64%7D%7D%7B%5Csqrt%5B3%5D%7B27%7D%7D%3Dr%20%5C%5C%0Ar%3D%5Cfrac%7B4%7D%7B3%7D)
It might be d but i’m not sure
Answer:
Step-by-step explanation:
The number of riders decreased.
Answer:
The distance from sea level in mm is 0.5494 mm.
Step-by-step explanation:
Consider the provided information.
It is given that Our scale is that 100 mm on the map is equal to 6371 km in Earth.
This can be written as:
100 mm = 6371 km
Divide both the sides by 6371.
100/6371 mm = 1 km
We need to find the distance from sea level in mm, if the distance is 35 km.
Multiply both sides by 35.
100/6371 × 35 mm = 1 × 35 km
0.5494 mm = 35 km
Hence, the distance from sea level in mm is 0.5494 mm.