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4 years ago

Need help asap!!!! Help me finish school

SAT

1 answer:

sineoko [7]4 years ago

4 0

Based of the research I just made about the CLEP exam, D. seems like the appropriate answer.

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If the aluminum block is initially at 25 ∘c , what is the final temperature of the block after the evaporation of the alcohol? a

Bumek [7]

The temperature of an object is how cold or hot it is.

The final temperature is 12.3 degrees Celsius

<h3>How to determine the final temperature </h3>

The given parameters are:

$\Delta H_{vap} = 45.4\ kJ/mol$ --- the heat of vaporization

$C_p = 0.903J/g^oC$ --- the specific heat of Aluminum

$m = 1.12g$ --- the mass of alcohol

$M = 60.1g/mol$ -- the molecular mass of alcohol

Start by calculating the moles of alcohol using:

$Moles = \frac{Mass}{Molecular\ Weight}$

So, we have:

$n = \frac{1.12g}{60.1g/mol}$

$n= 0.0186\ mol$

Next, calculate the amount of heat absorbed by the alcohol using:

$n * \Delta H_{vap} = -m_{alcohol}* C_p * \Delta T$

The mass of alcohol is 73 grams. So, we have:

$0.0186 * 45.4 = -73* 0.903 * \Delta T$

Evaluate the products

$0.84 = -65.92* \Delta T$

Divide both sides by -65.92

$\Delta T = -0.0127$

Express as degrees Celsius

$\Delta T = -12.7$

Also, we have:

$\Delta T = T_i - T_f$ --- the difference in the initial and the final temperatures.

This gives

$-12.7 = T_f - 25$

Collect like terms

$T_f = 25 - 12.7$

$T_f = 12.3$

Hence, the final temperature is 12.3 degrees Celsius