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Radda [10]
3 years ago
10

Find the simple interest.

Mathematics
1 answer:
Mademuasel [1]3 years ago
8 0
We need to compute the exact number of days of the loan.

Given:
Loan: 1,870
rate: 11%
term: Oct. 5 to Jan 16.

Oct 5-Oct 31: 26 days
Nov: 30 days
Dec: 31 days
Jan 16: 16 days.
total number of days: 103 days.

Interest = Principal * rate * term
Interest = 1870 * 0.11 * 103/365
Interest = 58.05

Given:
Promissory note $5,380
rate 6.2%
term: July 15 to Dec. 28

July 15 - 31 = 16 days
August: 31 days
September: 30 days
October: 31 days:
November: 30 days
December: 28 days
Total number of days is 166 days

Interest = Principal * rate * term
Interest = 5,380 * 0.062 * 166/365
Interest = 151.70
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Answer:

the greatest common factor is 3

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In B E C, F is the centroid, and AC = 12. Find A F and F C
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bearing in mind that the centroid in a triangle cuts each of the three medians in a 2:1 ratio.

since we know that A C = 12, let's split it in a 2:1 ratio then, cleary from the picture the larger is F C, so F C : A F is on a 2:1 ratio.

\bf A C=A F+F C\qquad \qquad \cfrac{F C}{A F}=\cfrac{2}{1}\qquad \qquad \cfrac{2\cdot \frac{12}{2+1}}{1\cdot \frac{12}{2+1}}\implies \cfrac{2\cdot 4}{1\cdot 4}\implies \cfrac{8}{4}

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Which expression represents the product of 83 and x
anzhelika [568]
The product is the result of multiplication

so the product of 83 and x is : 83x
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The center of a hyperbola is located at the origin. One focus is located at (−50, 0) and its associated directrix is represented
leva [86]

The equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)

As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin: \frac{x^{2}}{a^{2}}  - \frac{y^{2}}{b^{2}}    = 1

The distance from center to focus is 'c' and here focus is at (-50,0)

So, c= 50

Now if the distance from center to the directrix line is 'd', then

d= \frac{a^{2}}{c}

Here the directrix line is given as : x= 2304/50

Thus, \frac{a^{2}}{c}  = \frac{2304}{50}

⇒ \frac{a^{2}}{50}  = \frac{2304}{50}

⇒ a² = 2304

⇒ a = √2304 = 48

For hyperbola, b² = c² - a²

⇒ b² = 50² - 48² (By plugging c=50 and a = 48)

⇒ b² = 2500 - 2304

⇒ b² = 196

⇒ b = √196 = 14

So, the equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

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