Estimate it’s the length in meters for poster. Explain

AlekseyPX

Complete question :

Put these fraction in order of size smallest to largest : 7/10, 2/3, 4/5, 11/15

Answer:

2/3, 7/10, 11/ 15, 4 /5

Step-by-step explanation:

In other to make solving the question easier, we can convert the fractions to decimal in other to make comparison easier :

7/10 = 0.7

2/3 = 0.667

4 /5 = 0.8

11 /15 = 0.733

Using the placement or how the numbers will appear to the right of a number line ;

0.667, 0.7, 0.733, 0.8

Thus we have :

2/3, 7/10, 11/ 15, 4 /5

3 0

3 years ago

Find the slope of the line through each pair of points (11, 18) (20, 12)

JulijaS [17]

Answer:

2/3

Step-by-step explanation:

We can find the slope by using the slope formula

m = ( y2-y1)/(x2-x1)

= ( 12-18)/(20 -11)

= -6/-9

= 2/3

3 0

3 years ago

PLEASE HELP I WILL MARK BRAINLIEST!<br> Question is in the image.

deff fn [24]

Answer:

8

Step-by-step explanation:

The interquartile range of a data set is the difference between the upper and lower quartiles.

First, put the values in order from least to greatest:

8, 9, 9, 9, 10, 11, 13, 15, 17, 18, 22

To find the upper quartile, we need to first find the median.

The median of this data set is 11, because it is in the middle of the values.

The upper quartile is the median of all the numbers to the left of 11.

The median of 8, 9, 9, 9, and 10 is 9, because it's in the middle.

So the upper quartile is 9.

The lower quartile is the same, but to the right of 11. The median of 13, 15, 17, 18, and 22 is 17 because it's in the middle.

Now, to find the interquartile range, find the difference between 18 and 9.

17 - 9 = 8

5 0

3 years ago

Who does gyro never never ever bet on even numbers math worksheet!!

uranmaximum [27]

I really do not know the answer to this question

6 0

3 years ago

The amount of coffee that a filling machine puts into an 8-ounce jar is normally distributed with a mean of 8.2 ounces and a sta

nordsb [41]

Answer:

73.30% probability that the sampling error made in estimating the mean amount of coffee for all 8-ounce jars by the mean of a random sample of 100 jars will be at most 0.02 ounce

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\mu = 8.2, \sigma = 0.18, n = 100, s = \frac{0.18}{\sqrt{100}} = 0.018$

What is the probability that the sampling error made in estimating the mean amount of coffee for all 8-ounce jars by the mean of a random sample of 100 jars will be at most 0.02 ounce?

This is the pvalue of Z when X = 8.2 + 0.02 = 8.22 subtracted by the pvalue of Z when X = 8.2 - 0.02 = 8.18. So

X = 8.22

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{8.22 - 8.2}{0.018}$

$Z = 1.11$

$Z = 1.11$ has a pvalue of 0.8665

X = 8.18

$Z = \frac{X - \mu}{s}$

$Z = \frac{8.18 - 8.2}{0.018}$

$Z = -1.11$

$Z = -1.11$ has a pvalue of 0.1335

0.8665 - 0.1335 = 0.7330

73.30% probability that the sampling error made in estimating the mean amount of coffee for all 8-ounce jars by the mean of a random sample of 100 jars will be at most 0.02 ounce

8 0

3 years ago