Independent variable it always the variable that will change
Answer:
0.0225
Explanation:
According to the given information, the gene under study has two alleles. The frequency of one allele is 0.15. The locus is at Hardy–Weinberg equilibrium. This means that the sum of the frequencies of two alleles would be one. The frequency of homozygotes for an allele in the population is calculated as the square of the frequency of that allele.
Therefore, if the frequency of one allele in the population is = 0.15. Frequency of homozygotes for this allele in the population would be = 0.15 x 0.15 = 0.0225
Answer:
q = 0.2, p = 0.8
Explanation:
According to Hardy-Weinberg equilibrium,
p + q = 1
p² + 2pq + q² = 1 where,
p = frequency of dominant allele
q = frequency of recessive allele
p² = frequency of homozygous dominant genotype
2pq = frequency of heterozygous genotype
q² = frequency of homozygous recessive genotype
Here,
q² = aa = 0.04
q = √0.04 = 0.2
p = 1 - q
= 1 - 0.2
= 0.8
