Answer:
The factor is 11x - 2y ⇒ 2nd answer
Step-by-step explanation:
* Lets explain how to factorize the difference of two cubes
- If we want to factorize x³ - y³
- The binomial x³ - y³ is different of two cubes, because x³ is cube x
and y³ is cube y
- The difference of two cubes has two factors one two two terms and
the other is three terms
- To factorize it we find the ∛x³ and ∛y³
→ ∛x³ = x and ∛y³ = y
→ Then the first factor is (x - y)
→ We find the second factor from the first factor
→ square x
→ square y
→ Multiply x and y and put them between x² and y² with opposite sign
of the first factor
→ The second factor is (x² + xy + y²)
* Lets do the same with 1331x³ - 8y³
∵ ![\sqrt[3]{1331x^{3}}=11x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1331x%5E%7B3%7D%7D%3D11x)
∵ ![\sqrt[3]{8y^{3}}=2y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8y%5E%7B3%7D%7D%3D2y)
∴ The first factor is (11x - 2y)
∵ (11x)² = 121x²
∵ (2y)² = 4y²
∵ 11x × 2y = 22xy
∵ The sign of first factor is (-)
∴ The second factor is (121x² + 22xy + 4y²)
∴ <em>The factor is 11x - 2y </em>
Answer: The answer is
-
-
Step-by-step explanation:
The first thing you want to do is to add the
to the other one. You add instead of subtracting because the second one has a minus sign, and there is a minus sign in front of the parentheses. Two minus' make a plus. Adding these two together gives you a sum of
.
Next, you want to simplify 9cw. Remember that since 9cw is positive, and there is a minus sign if front of the parentheses, you need to subtract here. Subtracting 3cw and 9cw gives you a difference of
. The new equation is
.
Finally, we need to combine -w2 with -6w2. Remember that -w2 has a minus sign in front of it, so you need to add w2 to -6w2. This gives you
. You combine this answer with the two answers above, and you get:
. I hope this helps.
Answer:
(4, 1)
Step-by-step explanation:
x^2 + y^2 - 2y - 8x - 19 = 0
We rearrange the terms and complete the square twice.
x^2 - 8x + y^2 - 2y = 19
x^2 - 8x + 16 + y^2 - 2y + 1 = 19 + 16 + 1
(x - 4)^2 + (y - 1)^2 = 6^2
The center is (4, 1)