y = 1/2x + 3
change x and y
x = 1/2y + 3
now find the value of y and that is inverse function
x - 3 =1/2 y
y = 2x- 6
f-(x) = 2x - 6
<u />
for both domain : ( - ∞ , + ∞ )
range f (x) : ( - ∞ , + ∞ ) - { 0 }
range f-(x) :( -∞ , +∞)
Given:
The graph of a quadratic function passes through the points (5,31) (3,11) (0,11).
To find:
The equation of the quadratic function.
Solution:
A quadratic function is defined as:
...(i)
It is passes through the point (0,11). So, substitute 
in (i).
Putting 
in (i), we get
...(ii)
The quadratic function passes through the point (5,31). So, substitute 
in (ii).
Divide both sides by 5.
...(iii)
The quadratic function passes through the point (3,11). So, substitute 
in (ii).
Divide both sides by 3.
...(iv)
Subtracting (iv) from (iii), we get
Putting 
in (iv), we get
Putting 
in (ii), we get
Therefore, the required quadratic equation is .
1,2,3,5,6,10,15,30 because by looking at the number at the ones place, when it is 0 or an odd number, it could be divided by 2. When the places are added together and when it is divisible by 3, it is the factor of 3. Also, when there are 2 and 3 as a factor, it is also divisible by 6.
Answer:
9/22
Step-by-step explanation:
1/2 + x=10/11
Subtract 1/2 from each side
1/2-1/2 + x=10/11-1/2
x = 10/11 -1/2
Getting a common denominator of 22
x = 10/11*2/2 -1/2 *11/11
x = 20/22 - 11/22
x = 9/22
Answer:
15/7
Step-by-step explanation:
15/7
15 of 7 is the same as 15 out of 7, or 15/7
<em>I hope this helps! :)</em>
