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My name is Ann [436]
3 years ago
5

Given the declaration

Computers and Technology
1 answer:
STALIN [3.7K]3 years ago
7 0

Answer:

False

Explanation:

There's only one component of the array list which is list[0] which has value 50

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Vivian wants to increase the storage capacity of her computer. Which components should she upgrade?
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Answer:

Hard drive

Explanation:

The hard drive is where the operating system, programs and data reside on (unless the data is saved and backed up elsewhere). An older hard drive that uses platters for reading and writing data to it will be slower than a later model solid state device. Newer hard drives have very fast access speeds compared to older units.

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Propose a data structure that supports the stack push and pop operations and a third operation findMin, which returns the smalle
juin [17]

Answer: attached below

Explanation:

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To display data in a certain manner, like alphabetical order, is called
taurus [48]

Answer:

D. Sorting

hope this helps!

6 0
3 years ago
Assume that a program uses the named constant PI to represent the value 3.14. The program uses the named constant in several sta
mihalych1998 [28]

Answer:

The advantage for the above condition is as follows:-

Explanation:

  • If a user creates a defined constant variable and assigns a value on its and then uses that variable instead of the value, then it will a great advantage.
  • It is because when there is a needs to change the value of that variable, then it can be done when the user changes the value in one place. There is no needs to change the vale in multiple places.
  • But if there is a value in multiple places instead of a variable and there is no constant variable, then the user needs to change the value in multiple places.
7 0
3 years ago
an IPv6 packet has a 40 byte base header, a 20 byte destination options extension header (which is not used for routing) and 200
NISA [10]

Answer:

Explanation:

Given, total payload is: 2000 bytes

 MTU is: 1500 bytes

 Header is: 20 bytes

 Base header is: 40 bytes

Total number of fragments = Total Payload / MTU

                                            = 2500 / 1500

                                            = 2 fragments

Fragment     Base header    Fragmentation header     Authentication  

                                                                                                     header + Data

1                  40 bytes                  8 bytes                              20 bytes +772bytes

2                 40 bytes                   8 bytes                                 792 bytes

7 0
3 years ago
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