Answer:
(-15)
Step-by-step explanation:
10-25 = (-15)
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Answer:
Answer=B
Step-by-step explanation:
when something reflects across the y-axis it's value of x change it's sign so,
points KLM will change to:
K(1,3) to (-1,3)
L(3,4) to (-3,4)
M(4,1) to (-4,1)
this all goes with the triangle in answer B
Answer:
A and B are not independent events because P(A|B)≠P(A)
is the correct answer.
Step-by-step explanation:
If A and B are independent then we must have
P(AB) = P(A) P(B) and also
P(A/B) = P(A)
We are given that
A and B are two events.
Let P(A)=0.5 , P(B)=0.25 , and P(A and B)=0.15 .
P(A/B) = P(AB)/P(B) = 0.15/0.5 = 0.3
i.e. P(A/B) is not equal P(A)
Similarly P(B/A) = P(AB)/P(A) = 0.15/0.25 = 0.6 not equal to P(B)
Hence A and B are not independent.
Answer: (A) The image of JKL after a 90° counterclockwise about the origin is shown in figure 1. (B) The image of JKL after a reflection across the y-axis is shown in figure 2.
Explanation:
(A)
From the given figure it is noticed that the coordinate points are J(-4,1), K(-4,-2) and L(-3,-1).
If a shape rotate 90 degree counterclockwise about the origin, then,
![(x,y)\rightarrow (-y,x)](https://tex.z-dn.net/?f=%28x%2Cy%29%5Crightarrow%20%28-y%2Cx%29)
![J(-4,1)\rightarrow J'(-1,-4)](https://tex.z-dn.net/?f=J%28-4%2C1%29%5Crightarrow%20J%27%28-1%2C-4%29)
![K(-4,-2)\rightarrow K'(2,-4)](https://tex.z-dn.net/?f=K%28-4%2C-2%29%5Crightarrow%20K%27%282%2C-4%29)
![L(-3,-1)\rightarrow L'(1,-3)](https://tex.z-dn.net/?f=L%28-3%2C-1%29%5Crightarrow%20L%27%281%2C-3%29)
Therefore, the vertex of imare are J'(-1,-4), K'(2,-4) and L'(1,-3). The graph is shown in figure (1).
(B)
If a figure reflect across the y-axis then,
![(x,y)\rightarrow (-x,y)](https://tex.z-dn.net/?f=%28x%2Cy%29%5Crightarrow%20%28-x%2Cy%29)
![J(-4,1)\rightarrow J''(4,1)](https://tex.z-dn.net/?f=J%28-4%2C1%29%5Crightarrow%20J%27%27%284%2C1%29)
![K(-4,-2)\rightarrow K''(2,-4)](https://tex.z-dn.net/?f=K%28-4%2C-2%29%5Crightarrow%20K%27%27%282%2C-4%29)
![L(-3,-1)\rightarrow L''(3,-1)](https://tex.z-dn.net/?f=L%28-3%2C-1%29%5Crightarrow%20L%27%27%283%2C-1%29)
Therefore, the vertex of imare are J''(4,1), K''(2,-4) and L''(3,-1). The graph is shown in figure (2).