Question

Evaluate 8a+3b-10+c^28a+3b−10+c 2 8, a, plus, 3, b, minus, 10, plus, c, squared when a=2a=2a, equals, 2, b=5b=5b, equals, 5, and c=4c=4c, equals, 4.

Answer 1

Answer:

Final answer is 37 after evaluating.

Step-by-step explanation:

The given equation is,$8 a+3 b-10+c^{2}$

Here a= 2, b=5, c = 4

We need to evaluate the equation.

Substituting the values in the equation we get,

$8 a+3 b-10+c^{2}$

$=(8 \times 2)+(3 \times 5)-10+4^{2}$

Using Multiplication property we get;

$= 16 +15 -10 +16$

Using addition property  and subtraction property we get,

$=32 +5$

On simplifying equation using addition property we get,

$=37$

Hence Final answer is 37 after evaluating.

Answer 2

Answer:

its 37

Step-by-step explanation: