A. x^2 + b^2 = c^2
x^2 + 18^2 = 30^2
x^2 + 324 = 900
x^2 = 900 - 324
x^2 = 576
x = sqrt 576
x = 24 <===
b. (2x + 20) + (2x) + (x) + (3x + 20) = 360
8x + 40 = 360
8x = 360 - 40
8x = 320
x = 320/8
x = 40
2x + 20 = 2(40) + 20 = 80 + 20 = 100
2x = 2(40) = 80
3x + 20 = 3(40) + 20 = 120 + 20 = 140
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Explanation:
The product of the lengths of the segments of one chord is equal to the product of the lengths of the segments of the other chord. (The lengths are measured from the point of intersection of the chords to the points of intersection of the chord with the circle.)
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<em>Additional comment</em>
This relationship can be generalized to include the situation where the point of intersection of the lines is <em>outside</em> the circle. In that geometry, the lines are called secants, and the segment measures of interest are the measures from their point of intersection to the near and far intersection points with the circle. Again, the product of the segment lengths is the same for each secant.
This can be further generalized to the situation where the two points of intersection of one of the secants are the same point--the line is a <em>tangent</em>. In that case, the segment lengths are both the same, so their product is the <em>square</em> of the length of the tangent from the circle to the point of intersection with the secant.
So, one obscure relationship can be generalized to cover the relationships between segment lengths in three different geometries. I find it easier to remember that way.
I think it would be like
3 Time 2 and time 1 so number one is 6
and number 2 is 24
Answer:
The width of the rectangle is 5 meters, while the length of the rectangle is 12 meters.
Step-by-step explanation:
Given that the perimeter of a rectangle is twice the sum of its lenght and its width, and the perimeter is 34 meters and its lenght is 2 meters more than twice its width, to determine the length and width of the rectangle the following calculation must be done:
(2X + 2 + X) x 2 = 34
(3X + 2) x 2 = 34
6X + 4 = 34
6X = 34 - 4
X = 30/6
X = 5
(2x5 + 2 + 5) x 2 = 34
(10 + 2 + 5) x 2 = 34
17 x 2 = 34
34 = 34
Therefore, the width of the rectangle is 5 meters, while the length of the rectangle is 12 meters.
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