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Bess [88]
4 years ago
7

After mixing sand with water, after awhile it settles to the bottom. WHY?

Chemistry
2 answers:
IceJOKER [234]4 years ago
8 0

Answer:

Mass/Volume

Explanation:

The sand eventually makes it way to the bottom because of its mass/volume compared to the waters density. Just like while swimming in a pool, we sink to the bottom because of our mass/volume.

BigorU [14]4 years ago
4 0

Answer:

Because the water is filled up with the sand every where

Explanation:

So the exess sand goes to the bottem

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A student obtains a 10.0g sample of a white powder labeled as BaCl2. After completely dissolving the powder in 50.0mL of distill
LekaFEV [45]

Answer:

Whether barium chloride solution was pure

Explanation:

We may answer whether barium chloride was pure. The sequence of this experiment might be depicted by the following balanced chemical equations:

BaCl_2 (aq)\rightarrow Ba^{2+} (aq) + 2 Cl^- (aq)

Ba^{2+} (aq) + SO_4^{2-} (aq)\rightarrow BaSO_4 (s)

Having a total sample of 10.0 grams, we would firstly find the mass percentage of barium in barium chloride:

\omega_{Ba^{2+}} = \frac{M_{Ba}}{M_{BaCl_2}} = \frac{137.327 g/mol}{208.23 g/mol\cdot 100\% = 65.95 \%

This means in 10.0 g, we have a total of:

m_{Ba^{2+}} = 10.0 g\cdot 0.6595 = 6.595 g of barium cations.

The precipitate is then formed and we measure its mass. Having its mass determined, we'll firstly find the percentage of barium in barium sulfate using the same approach:

\omega_{Ba} = \frac{137.327 g/mol}{233.38 g/mol}\cdot 100\% = 58.84 \%

Multiplying the mass we obtained by the fraction of barium will yield mass of barium in barium sulfate. Then:

  • if this number is equal to 6.595 g, we have a pure sample of barium chloride;
  • if this number is lower than 6.595 g, this means we have an impure sample of barium chloride, as we were only able to precipitate a fraction of 6.595 g.
3 0
3 years ago
There are long, underwater mountain chains that divide the sea
natima [27]

Mid-Ocean Ridges

Two examples of Mid-Ocean Ridges are the Mid-Atlantic Ridge and the East Pacific Rise.

Explanation:

Mid-ocean ridges are mountain-like geographical features on the ocean floor. They usually line along the divergent boundaries of tectonic plates moving away from each other. This is because as the plates move in opposite direction, the vacuum in between the plates is filled by upwelling magma from the mantle. Usually the texture of the rocks that form these mountain ridges has bands. This is because, before the magma cools, the iron in the magma (due to its ferromagnetic property) aligns with the earths magnetic field. The earth magnetic flux flips over several 1000 years hence these bands orient themselves differently depending on the magnetic field orientation at the time they were formed.

Learn More:

For more on mid-ocean ridges check out;

brainly.com/question/7666628

#LearnWithBrainly

4 0
3 years ago
Guys please help me with this question!
damaskus [11]
A reducing agent is one which is oxidised in the reaction itself. When you take into account the oxidation numbers you will see that the Cl- ions are oxidised from an oxidation number of -1 to 0 in Cl2. Therefore Cl- ions are the reducing agent.
3 0
3 years ago
How<br> much heat must be added to<br> 85g<br> of water<br> to raise its temperature 225?
ki77a [65]

Answer:

One of water's most significant properties is that it takes a lot of heat to it to make it get hot. Precisely, water has to absorb 4,184 Joules of heat (1 calorie) for the temperature of one kilogram of water to increase 1°C.

Explanation:

7 0
3 years ago
Determine the mass of each of t he following:
EastWind [94]

Explanation:

Mass of compounds = Moles of compound × Molecular mass of compound

a) Moles of LiCl = 2.345 mol

Molecular mass of LiCl = 42.5 g/mol

Mass of 2.345 moles of LiCl = 2.345 mol × 42.5 g/mol = 99.6625 g

b) Moles of acetylene = 0.0872 mol

Molecular mass of acetylene= 26 g/mol

Mass of 0.0872 moles acetylene= 0.0872 mol × 26 g/mol = 2.2672 g

c) Moles of sodium carbonate= 3.3\times 10^{-2}mol

Molecular mass of sodium carbonate= 106 g/mol

Mass of  3.3\times 10^{-2}mol sodium carbonate

=  3.3\times 10^{-2}mol\times 106 g/mol= 3.498 g

d) Moles of fructose = 1.23\times 10^3 mol

Molecular mass fructose= 180 g/mol

Mass of  1.23\times 10^3 mol fructose

=  1.23\times 10^3mol\times 180 g/mol = 221,400 g

e) Moles of  FeSO_4(H_2O)_7=0.5758 mol

Molecular mass of FeSO_4(H_2O)_7 =278 g/mol

Mass of  1.23\times 10^3 mol fructose

=  0.5758 mol\times 278 g/mol= 160.0724 g

3 0
3 years ago
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