Answer:6
Step-by-step explanation:
The position function of a particle is given by:

The velocity function is the derivative of the position:

The particle will be at rest when the velocity is 0, thus we solve the equation:

The coefficients of this equation are: a = 2, b = -9, c = -18
Solve by using the formula:
![t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
Substituting:
![\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20t%3D%5Cfrac%7B9%5Cpm%5Csqrt%5B%5D%7B81-4%282%29%28-18%29%7D%7D%7B2%282%29%7D%20%5C%5C%20t%3D%5Cfrac%7B9%5Cpm%5Csqrt%5B%5D%7B81%2B144%7D%7D%7B4%7D%20%5C%5C%20t%3D%5Cfrac%7B9%5Cpm%5Csqrt%5B%5D%7B225%7D%7D%7B4%7D%20%5C%5C%20t%3D%5Cfrac%7B9%5Cpm15%7D%7B4%7D%20%5Cend%7Bgathered%7D)
We have two possible answers:

We only accept the positive answer because the time cannot be negative.
Now calculate the position for t = 6:
Answer:
24 hours
Step-by-step explanation:
One member of the gardening club can alone plant flowers in 12 hours.
So in 1 hour he can plant 1/12 of the flowers.
Let the time required by the second member of the club to plant flowers alone be x hours.
Then in 1 hour he can plant 1/x of the flowers.
Now when the two members work together,each hour they can plant:
of the flowers.
But they can together complete the job in 8 hours. So in one hour they plant 1/8 of the flowers.
=> ![\[\frac{1}{12}+\frac{1}{x}=\frac{1}{8}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B1%7D%7B12%7D%2B%5Cfrac%7B1%7D%7Bx%7D%3D%5Cfrac%7B1%7D%7B8%7D%5C%5D)
=> ![\[\frac{1}{x}=\frac{1}{24}\] ](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B1%7D%7Bx%7D%3D%5Cfrac%7B1%7D%7B24%7D%5C%5D%0A)
=> x=24
So the second member can plant the flowers alone in 24 hours
Answer: The required value is

Step-by-step explanation: The given functions are:

We are given to find the value of 
We know that, if s(x) and t(x) are any two functions of a variable x, then we have

Therefore, we have

Thus, the required value is

Answer:
The correct options are: Interquartile ranges are not significantly impacted by outliers. Lower and upper quartiles are needed to find the interquartile range. The data values should be listed in order before trying to find the interquartile range. The option Subtract the lowest and highest values to find the interquartile range is incorrect because the difference between lowest and highest values will give us range. The option A small interquartile range means the data is spread far away from the median is incorrect because a small interquartile means data is nor spread far away from the median