What is 3.868x10^9 in standard form

2 answers:

8 0

$\bf \stackrel{\textit{scientific form}}{3.868\times 10^9}\implies \stackrel{\textit{standard form}}{3\underline{868000000.}}\qquad \leftarrow \begin{array}{llll} 10^9\textit{ means we move the }\\ \textit{dot 9 slots to the right} \end{array} \\\\\\ ~\hspace{10em}3868000000$

goldfiish [28.3K]4 years ago

4 0

An easier way to do this would to be move the decimal spot 9 places to the right so that would be 3868000000 because u moved the decimal spot past the eight(1) past the 6 (2) past eight (3) and past 6 makes zeros to make it nine decimal spots

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Answer:

a) 30.08% probability the sample mean will be within $100 of the population mean.

b) 0% probability the sample mean will be greater than $12,600

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the Central Limit Theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .