Check the picture below.
so the perimeter of the kite is x+x+y+y, namely 2x + 2y.
![\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=\stackrel{hypotenuse}{x}\\ a=\stackrel{adjacent}{8}\\ b=\stackrel{opposite}{15}\\ \end{cases} \\\\\\ x=\sqrt{8^2+15^2}\implies x=\sqrt{289}\implies \boxed{x=17} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Busing%20the%20pythagorean%20theorem%7D%20%5C%5C%5C%5C%20c%5E2%3Da%5E2%2Bb%5E2%5Cimplies%20c%3D%5Csqrt%7Ba%5E2%2Bb%5E2%7D%20%5Cqquad%20%5Cbegin%7Bcases%7D%20c%3D%5Cstackrel%7Bhypotenuse%7D%7Bx%7D%5C%5C%20a%3D%5Cstackrel%7Badjacent%7D%7B8%7D%5C%5C%20b%3D%5Cstackrel%7Bopposite%7D%7B15%7D%5C%5C%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20x%3D%5Csqrt%7B8%5E2%2B15%5E2%7D%5Cimplies%20x%3D%5Csqrt%7B289%7D%5Cimplies%20%5Cboxed%7Bx%3D17%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf \begin{cases} c=\stackrel{hypotenuse}{y}\\ a=\stackrel{adjacent}{8}\\ b=\stackrel{opposite}{4}\\ \end{cases}\implies y=\sqrt{8^2+4^2}\implies y=\sqrt{80}\implies \boxed{y\approx 8.94} \\\\[-0.35em] ~\dotfill\\\\ 2x+2y\implies 2(17)+2(8.94)\implies 51.88\implies \stackrel{\textit{rounded up more}}{51.9}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%20c%3D%5Cstackrel%7Bhypotenuse%7D%7By%7D%5C%5C%20a%3D%5Cstackrel%7Badjacent%7D%7B8%7D%5C%5C%20b%3D%5Cstackrel%7Bopposite%7D%7B4%7D%5C%5C%20%5Cend%7Bcases%7D%5Cimplies%20y%3D%5Csqrt%7B8%5E2%2B4%5E2%7D%5Cimplies%20y%3D%5Csqrt%7B80%7D%5Cimplies%20%5Cboxed%7By%5Capprox%208.94%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%202x%2B2y%5Cimplies%202%2817%29%2B2%288.94%29%5Cimplies%2051.88%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Brounded%20up%20more%7D%7D%7B51.9%7D)
Answer:
The absolute value of -1 is 1
Step-by-step explanation:
Absolute value is how far a number is from 0 on a number line. Since you can't have a negative amount of spaces, the answer is 1
Answer:
x = ±√11 +2
Step-by-step explanation:
Given in the question an equation,
x²- 4x - 7 = 0
Step 1
take 7 to the right side of equation
x²- 4x = 7
Step 2
To create a trinomial square on the left side of the equation, find a value that is equal to the square of half of b, the coefficient of x
2ab = -4x
2xb = -4x
b = -2
Step 3
Take square of b and add it to each side of the equation.
x²- 4x + (-2)²= 7 + (-2)²
x²- 4x + 4 = 7 + 4
x²- 4x + 4 = 11
Step 4
Factor the perfect trinomial square
(x−2)² = 11
Step 5
take square root on both sides
√(x−2)² = √11
(x-2) = ±√11
x = ±√11 +2
Answer:
19,27 cm^2
Step-by-step explanation:
area of triangle = (6 x 3)/ 2 = 9 cm^2
circle area : 3^2 x 3,14 = 28,27 cm^2
area of shaped region = 28,27 - 9 = 19,27 cm^2
