Find the difference between ( x+ 5) and (2x+3)

Aurora Corporation operated without insurance coverage for the first month of 2015. Then, on February 1, 2015, the company paid

vitfil [10]

Answer:

$2200

Step-by-step explanation:

$4800 premium for 2 years means for 2* 12 = 24 months, thus each month, the insurance expense is:

4800/24 = 200 dollars

Since they haven't used insurance in January, they will use insurance expense for the rest of the 12 - 1 = 11 months, thus the expense would be:

200 * 100 = $2200

4 0

3 years ago

The length of a living room is 12 feet and its width is 1012 feet. The length of the room is being expanded by x feet. Choose an

Ivanshal [37]

Answer:

Option C. 10.5(12 + x) square feet

Option E. (126 + 10.5x) square feet

Step-by-step explanation:

step 1

Find the area of the original living room

we know that

The area of the original living room is equal to

$A=LW$

we have

$L=12\ ft\\W=10\frac{1}{2}\ ft=10.5\ ft$

substitute

$A=(12)(10.5)=126\ ft^2$

step 2

Find the new area of the living room

The length of the room is being expanded by x feet

so

we have

$L=(12+x)\ ft\\W=10.5\ ft$

The new area is

$A=10.5(12+x)\ ft^2$

The expanded form of the expression is

Apply distributive property

$A=10.5(12)+10.5(x)\\A=(126+10.5x)\ ft^2$

6 0

3 years ago

Hannah has a biased coin.

nasty-shy [4]

Answer:

60

Step-by-step explanation:

200 x 0.3 = 60

7 0

3 years ago

How does the graph of y = sec(x + 3) – 7 compare with the graph of y = sec(x)?

Alla [95]

Answer:

The function y = sec(x) shifted 3 units left and 7 units down .

Step-by-step explanation:

Given the function: y = sec(x)

If k is any positive real number, then the graph of f(x) - k is the graph of y = f(x) shifted downward k units.

If p is a positive real number, then the graph of f(x+p) is the graph of y=f(x) shifted to the left p units.

The function $y = \sec(x+3)-7$ comes from the base function y= sec(x).

Since 3 is added added on the inside, this is a horizontal shift Left 3 unit, and since 7 is subtracted on the outside, this is a vertical shift down 7 units.

Therefore, the transformation on the given function is shifted 3 units left and 7 units down

3 0

3 years ago

Read 2 more answers

Use matrices and elementary row to solve the following system:

LiRa [457]

I assume the first equation is supposed to be

$5x-3y+2z=13$

and not

$5x-3x+2x=4x=13$

As an augmented matrix, this system is given by

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]$

Multiply through row 3 by 1/2:

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]$

Add -1(row 2) to row 3:

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]$

Multiply through row 3 by 1/5:

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]$

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

$\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]$

Add -3(row 2) to row 1:

$\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]$

Multiply through row 1 by -1:

$\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]$

Add -2(row 1) to row 2:

$\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]$

Multipy through row 2 by -1:

$\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]$

The solution to the system is then

$\boxed{x=1,y=-2,z=1}$

5 0

3 years ago