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Aleksandr-060686 [28]
4 years ago
12

Find the area of the rhombus.

Mathematics
1 answer:
Vinvika [58]4 years ago
7 0
A =  \frac{1}{2}d_1d_2 = \frac{1}{2}*(4+4)(7+7)=  56 \ units^2
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Connor bought a pack of 4 notebooks for<br> $8.20. What was the unit price? please explain
Mamont248 [21]

Answer:

$2.05

Step-by-step explanation:

$8/4 notebooks= $2

.20/4=.05

________________

$2.05

3 0
3 years ago
Does anybody know this?
shusha [124]

Answer:

64

Step-by-step explanation:

128 divided by 2. Because the l on the lines mean its congruent

8 0
3 years ago
List the sample space for rolling two dice and finding the sum of the numbers. How many 8's are there in the sample space? [Assu
Reptile [31]
Using the given assumption, there are 3.

The sample space for rolling two dice and finding the sum is:

2   3   4   5   6    7 
3   4   5   6   7    8
4   5   6   7   8    9
5   6   7   8   9    10
6   7   8   9   10  11
7   8   9  10  11  12

From the sample space alone, there are 5.  However, since a 3 and a 5 is the same as a 5 and a 3, this means that 2, 6 is the same as 6, 2 as well; this takes 2 off of the 5, leaving us 3.
5 0
4 years ago
Find the GCF of 34 and 90
Nana76 [90]

Answer:

GCF is 2

Step-by-step explanation:

Factoring 34 leaves only 2 and 17.

90 is not divisible by 17 thus the GCF is 2.

6 0
3 years ago
What happens to the value of the expression 150-j150−j150, minus, j as jjj decreases?
nikklg [1K]

Answer:

The value of the expression increases as j decreases

Step-by-step explanation:

Let f(j) = 150 - j150 - j150

f(j) = 150 - j300

As j decreases, the value of j300 decreases (i.e the farther j300 is from 150). Due to the wider gap between 150 and j300, the value of f(j) increases.

For example:

When j = 1, f(j) = 150 - (300*1) = -150

When j = 0.5, f(j) = 150 - (300*0.5) = 0

When j = 0. f(j) = 150 - (300*0) = 150

It is obvious from the analogy above that the expression 150-j150−j150 increases as j decreases

4 0
4 years ago
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