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MissTica
3 years ago
6

The table shows Jose's rate of bicycle riding.

Mathematics
2 answers:
SpyIntel [72]3 years ago
5 0

Answer:Line B

Step-by-step explanation:

I hope this help :)

Naddik [55]3 years ago
5 0

Answer: Line B

Step-by-step explanation:

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What’s the answer to this? You have to estimate
bazaltina [42]
0.19579831 (that's what my math app said the estimate was)
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Factorise 125x^3 -27y^3
telo118 [61]

Answer:

(5x - 3y)(25x² +15xy + 9y²)

Step-by-step explanation:

125x³ - 27y³ is a difference of cubes and factors in general as

a³ - b³ = (a - b)(a² + ab + b²)

Given

125x³ - 27y³

= (5x)³ - (3y)³

= (5x - 3y)((5x)² + (5x)(3y) + (3y)²)

= (5x - 3y)(25x² + 15xy + 9y²)

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2 years ago
Who know the answer
Shkiper50 [21]
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3 0
3 years ago
(x+4) (x+10)<br>simplify​
Murrr4er [49]

Answer:

x^2 + 14x + 40.

Step-by-step explanation:

(x+4) (x+10)

= x(x + 10) + 4(x + 10)     ( By the Distributive Law)

= x^2 + 10x + 4x + 40

= x^2 + 14x + 40.

8 0
3 years ago
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Cherie is jogging around a circular track. She
skelet666 [1.2K]

Answer:

Measure of minor angle JOG is 95.5^{\circ}

Step-by-step explanation:

Consider a circular track of radius 120 yards. Assume that Cherie starts from point J and runs 200 yards up to point G.  

\therefore m JG = 200 yards, JO=120 yards.  

Now the measure of minor arc is same as measure of central angle. Therefore minor angle is the central angle \angle JOG = \theta.

To calculate the central angle, use the arc length formula as follows.  

Arc\:Length\left(s\right) = r\:\theta  

Where \theta is measured in radian.

Substituting the value,

200=120\:\theta  

Dividing both side by 120,

\dfrac{200}{120}=\theta  

Reducing the fraction into lowest form by dividing numerator and denominator by 40.

\therefore \dfrac{5}{3}=\theta  

Therefore value of central angle is \angle JOG = \theta=\left(\dfrac{5}{3}\right)^{c}, since angle is in radian

Now convert radian into degree by using following formula,

1^{c}=\left(\dfrac{180}{\pi}\right)^{\circ}

So multiplying \theta with \left(\dfrac{180}{\pi}\right)^{\circ} to convert it into degree.

\left(\dfrac{5}{3}\right)^{c}=\left(\dfrac{5}{3}\right) \times \left(\dfrac{180}{\pi}\right)^{\circ}

Simplifying,

\therefore \theta = 95.49^{circ}

So to nearest tenth, \angle JOG=95.5^{circ}

8 0
3 years ago
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