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elena55 [62]
3 years ago
5

Which equation should be used to graph y=sec^-1(x) on a calculator ?

Mathematics
1 answer:
erastova [34]3 years ago
4 0
Arcsecant or arcsec or sec⁻¹ is an inverse trigonometric function. And many calculators don't have a key for them because they can be calculated with basic trigonometric functions like so:

sec⁻¹(x)=cos⁻¹(1/x). 

So the correct answer is the fourth one: y=cos⁻¹(1/x).
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How do you answer this?
lidiya [134]
(a + b)^3 = a^3 + 3a^2b + 3ab^2+ b^3 
(a +(- b))^3 = (a-b)^2 =  a^3 - 3a^2b + 3ab^2- b^3  
7 0
4 years ago
How can 1/5x − 2 = 1/3x + 8 be set up as a system of equations? a . 5y − 5x = −10. 3y − 3x = 24 b. 5y − 5x = −10. 3y + 3x = 24 c
VMariaS [17]
The answer is d. 5y − x = −10. 3y − x = 24

\frac{1}{5}x-2=  \frac{1}{3}x+8=y
⇒   y= \frac{1}{5}x-2
      y= \frac{1}{3}x+8
________________________
y= \frac{x}{5} -2= \frac{x}{5} - \frac{10}{5} = \frac{x-10}{5}
y= \frac{x}{3} +8= \frac{x}{3} + \frac{24}{3} = \frac{x+24}{3}
________________________
y= \frac{x-10}{5}            ⇒     5y=x-10
y= \frac{x+24}{3}           ⇒     3y=x+24
________________________
5y-x=-10
3y-x=24
5 0
3 years ago
Jada made 316 gallons of lemonade. Jada served 56 gallon to her friends. How much lemonade does Jada have left? Enter your answe
GaryK [48]

Answer:

260 gallons of lemonade

Step-by-step explanation:

Step one:

given data

We are told that Jada made 316 gallons of lemonade.

and later served 56gallons of the lemonade

Required

The remaining Lemonade

Step two

We have the total lemonade as 316

and the deducted as 56

the balance will be

= 316-56

=260 gallons of lemonade

7 0
3 years ago
On a basketball team, the following players made most of the 56 points made during the last basketball game.
Ivanshal [37]

Answer:

7.75

Step-by-step explanation:

56-27-21-0.25=7.75

4 0
3 years ago
In order to determine the average weight of carry-on luggage by passengers in airplanes, a sample of 25 pieces of carry-on lugga
Fynjy0 [20]
To find the standard error, divide the standard deviation by the square root of the sample size

standard deviation = 7.5
sample size = 25......sqrt 25 = 5

standard error = 7.5 / 5 = 1.5 <==
6 0
3 years ago
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