All categories

2 years ago

Which equation should be used to graph y=sec^-1(x) on a calculator ?

1 answer:

4 0

Arcsecant or arcsec or sec⁻¹ is an inverse trigonometric function. And many calculators don't have a key for them because they can be calculated with basic trigonometric functions like so:

sec⁻¹(x)=cos⁻¹(1/x).

So the correct answer is the fourth one: y=cos⁻¹(1/x).

You might be interested in

What is the answer!!! Pls reply!!

Ulleksa [173]

2 11/12 is your answer because

3-2=1+1=2

and 4/12 - 3/12 = 1/12 + 10/12 = 11/12.

7 0

2 years ago

Select the three ratios that represent the number of red cars to blue cars.

Lorico [155]

Three ratios that represent the number of red cars to blue cars are

2 : 3

6 : 9

8 : 12

$\texttt{ }$

<h3>Further explanation</h3>

<u>Given:</u>

Number of Red Cars = 4

Number of Blue Cars = 6

<u>Asked:</u>

Ratio = ?

<u>Solution:</u>

<em>Number of Red Cars = R</em>

<em>Number of Blue Cars = B</em>

The ratio that represent the number of red cars to blue cars is :

$R : B = 4 : 6$

We can find other ratio by dividing or multiplying the above comparison with the same number :

$R : B = (4/2) : (6/2) = 2 : 3$

$R : B = (4 \times 2) : (6 \times 2) = 8 : 12$

$R : B = (4 \times \frac{3}{2}) : (6 \times \frac{3}{2}) = 6 : 9$

$\texttt{ }$

<h3>Conclusion:</h3>

Three ratios that represent the number of red cars to blue cars are:

2 : 3

6 : 9

8 : 12

$\texttt{ }$

<h3>Learn more</h3>

The LCM and HCF : brainly.com/question/420337
A car’s service book : brainly.com/question/422755
Verify that HCF × LCM = product of two numbers : brainly.com/question/10942748

<h3>Answer details</h3>

Grade: College

Subject: Mathematics

Chapter: Ratio

Keywords: Lower , Common , Multiple , Highest , Ratio , Proper , Jar , Pickles , Patties , Buns

4 0

2 years ago

Read 2 more answers

PLEASE HELP!!! YOU GET 10 BRAINLIST!!!! PLEASE SHOW ALL OF YOUR WORK/HOW YOU GOT THE ANSWER!!!

Mrrafil [7]

The answer is x< 9 so yeah

5 0

2 years ago

Read 2 more answers

Tonya and Leo each bought a cell phone at the same time. The trade-in values, in dollars, of the cell phones are modeled by the

Paha777 [63]

Answer:

The answer is Tonya's phone had the greater initial trade-in value.

Leo's phone decreases at an average rate slower than the trade in value of Tonya's phone.

Step-by-step explanation:

Given

Tonya

$f(x) = 490 * 0.88^x$

Leo

$x \to g(x)$

$0 \to 480$

$2 \to 360$

$4 \to 470$

Solving (a): The phone with greater initial value

The initial value is when x = 0. So, we have:

$f(x) = 490 * 0.88^x$

$f(0) = 490 * 0.88^0$

$f(0) = 490 * 1$

$f(0) = 490$

From Leo's table

$g(0) = 480$

By comparison;

$f(0) > g(0)$

i.e.

$490 > 480$

<em>So: Tonya's had the greater initial trade-in value</em>

Solving (b): The phone with lesser rate

An exponential function is:

$y = ab^x$

Where:

$b \to rate$

For Tonya

$b = 0.88$

For Leo, we have:

$(x_1,y_1) = (0,480)$

$(x_2,y_2) = (2,360)$

So, the equation becomes:

$y = ab^x$

$480 = ab^0$ and $360 = ab^2$

Solving $480 = ab^0$ , we have:

$480 = a * 1$

$480 = a$

$a= 480$

$360 = ab^2$ becomes

$360 = 480 * b^2$

Divide both sides by 480

$0.75 = b^2$

Take square roots

$0.87 = b$

$b=0.87$ -- Leo's rate

By comparison; Leo's rate is slower i.e. 0.87 < 0.88

6 0

2 years ago

I need 6x-10 ima not too good with these

Verizon [17]

x=11

the angles are congruent so 6x-10=56

6x=66

x=11

5 0

2 years ago