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3 years ago

I need help asap!! Thanks!

Mathematics

1 answer:

melomori [17]3 years ago

3 0

The answer is 28. I just did the math. no guessing

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What is the solution (x, y) to the system of equations shown?

iren2701 [21]

Answer:

Step-by-step explanation:

Glad to help

If you will have any questions about the way I solved it,

don't hesitate to ask

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3 years ago

Please help me on 32 thx :)

lapo4ka [179]

The answer is A because Katie saved twice as much as Rachel, plus five dollars more I think

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3 years ago

What is the value of y when x=9

Kazeer [188]

2/3 = 9/y
cross multiply
2y = 9 * 3
2y = 27
y = 27/2
y = 13.5 or 13 1/2

6 0

3 years ago

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X2 (6x+ 1) (3x-9) = 0

hjlf

Answer:

x = 0, $-\frac{1}{6}$ , 3

Step-by-step explanation:

Hey there!

<em />

<em>Step 1: Regroup terms.</em>

2x(6x + 1) (3x - 9) = 0

<em>Step 2: Solve for x.</em>

x = 0, $-\frac{1}{6}$ , 3

~I hope I helped you! :)~

3 0

3 years ago

Need help with this trigonometry word problem

fenix001 [56]

Answer:

$\huge \boxed{ \boxed{ \sf 6\sqrt{3} \: or \: 10.4}}$

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

trigonometry
PEMDAS

<h3>let's solve:</h3>

to find <u>how far the ladder is from the foot of the </u><u>wall </u>

we will use tan function because we are given opposite and angle

we need to find adjacent

$\quad \tan( \theta) = \dfrac{opp} {adj}$

let adjacent be BC

$\boxed{ \red{ \boxed{accoding \: to \: the \: question : }}}$

$\quad \: \tan( {60}^{ \circ} ) = \dfrac{6}{BC}$

we will use a little bit algebra to figure out BC

$\sf substitute \: the \: value \: of \: \tan( {60}^{ \circ} ) \: i.e \: \sqrt{3} : \\ \sqrt{3} = \frac{BC}{6}$
$\sf cross \: multiplication : \\ \therefore \: BC = 6\sqrt{3} \: or \: 10.4$

$\text{And we are done!}$

7 0

3 years ago

Read 2 more answers