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3 years ago

6

8ths on division pls help me I really need it

2 answers:

RideAnS [48]3 years ago

8 0

2 , 5 , 9 , 4 , 10 , 3 , 6 , 7 , 8 , 1
10 , 7 , 3 , 9 , 8 , 5 , 1 , 9 , 2 , 6
5 , 1 , 3 , 6 , 4 , 9 , 2 , 5 , 7 , 8

expeople1 [14]3 years ago

6 0

I'm going from left to right.
1. 2 2. 5 3. 9 4. 4 5. 10 6. 3 7. 6 8. 7 9. 8 10. 1 11. 10 12. 7 13. 3 14. 9 15. 8 16. 5 17. 1 18. 4 19. 2 20. 6 21. 5 22. 1 23. 3 24. 6 25. 4 26. 9 27. 2 28. 5 29. 7 30. 8

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What is the answer for 17x> -7

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3 years ago

URGENT HELP ME PLEASE

Trava [24]

Answer:

(a) $\log_3(\dfrac{81}{3})=3$

(b) $\log_5(\dfrac{625}{25})=2$

(c) $\log_2(\dfrac{64}{8})=3$

(d) $\log_4(\dfrac{64}{16})=1$

(e) $\log_6(36^4)=8$

(f) $\log(100^3)=6$

Step-by-step explanation:

Let as consider the given equations are $\log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?$ .

(a)

$\log_3(\dfrac{81}{3})=\log_3(27)$

$\log_3(\dfrac{81}{3})=\log_3(3^3)$

$\log_3(\dfrac{81}{3})=3$ $[\because \log_aa^x=x]$

(b)

$\log_5(\dfrac{625}{25})=\log_5(25)$

$\log_5(\dfrac{625}{25})=\log_5(5^2)$

$\log_5(\dfrac{625}{25})=2$ $[\because \log_aa^x=x]$

(c)

$\log_2(\dfrac{64}{8})=\log_2(8)$

$\log_2(\dfrac{64}{8})=\log_2(2^3)$

$\log_2(\dfrac{64}{8})=3$ $[\because \log_aa^x=x]$

(d)

$\log_4(\dfrac{64}{16})=\log_4(4)$

$\log_4(\dfrac{64}{16})=1$ $[\because \log_aa^x=x]$

(e)

$\log_6(36^4)=\log_6((6^2)^4)$

$\log_6(36^4)=\log_6(6^8)$

$\log_6(36^4)=8$ $[\because \log_aa^x=x]$

(f)

$\log(100^3)=\log((10^2)^3)$

$\log(100^3)=\log(10^6)$

$\log(100^3)=6$ $[\because \log10^x=x]$

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3 years ago

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3 years ago

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