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4 years ago

1

Mathematics

1 answer:

givi [52]4 years ago

5 0

Step-by-step explanation:

$d=3h+2\\h=\frac{d-2}{3} \\v=?$

$d=v*t\\\\v=\frac{d}{t}\\\\ v=\frac{3h+2}{\frac{d-2}{3} }\\\\v=(3h+2)(\frac{3}{d-2})\\ \\v=\frac{9h+6}{d-2}$

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I need help please my home work not to sure how to do it

Artyom0805 [142]

1. x+5y=8
2x- 5y=1 What you do is find the number/variable that are the same( here is is the +5y and -5y. You want them to be opposites(-,+) so that they cancel each other out. if they are not opposites, then multiply one equation by a negative sign to change it. Cross out the 5y's. Now you can combine like terms-x+2x=3x, and 8+1=9, so now your equation will look like this:
3x=9
x=9/3
x=3
now take x=3 and plug it into the first equation to solve for y. x+5y=8, so 3+5y=8
5y=8-3
5y=5
y=5/5
y=1
(3,1) are your answers.
now do the same with the other problems.

4 0

3 years ago

Read 2 more answers

A rectangle is formed by placing 2 identical squares side by side. The area of the rectangle is 98 cm2. What is the perimeter of

kherson [118]

The rectangle area is 98. So if you split it in half, you would get 2 squares. Half of 98 is 49.

If it is now a square, you now simply know, that 7*7=49. Meaning that The sides of the square are 7 each.

7 times the 4 sides equals 28. So the perimeter of one square is 28.

6 0

3 years ago

Pls if anyone knows the answer with work included/steps that will be greatly appreciated :)

dimaraw [331]

Answer:

1. Option D. 15x²

2. Option C. 3

Step-by-step explanation:

1. Determination of the area of one section.

Length (L) of one section = 25x/5 = 5x

Width (W) of one section = 3x

Area (A) of one section =?

The area of one section can be obtained as follow:

Area (A) = Length (L) × Width (W)

A = L × W

A = 5x * 3x

A = 15x²

Thus, the area of one section is 15x²

2. Determination of the expressions that are equivalent to (p²)³.

We'll begin by simplifying (p²)³. This can be obtained as follow:

(p²)³ = p²*³

(p²)³ = p⁶

Next we shall compare each expression given in the question above to see which will be the same as p⁶.

p × p × p × p × p × p = p¹⁺¹⁺¹⁺¹⁺¹⁺¹

p × p × p × p × p × p = p⁶

p² × p² × p² = p²⁺²⁺²

p² × p² × p² = p⁶

p² × p³ = p²⁺³

p² × p³ = p⁵

Thus,

p² × p³ ≠ p⁶

p⁵ ≠ p⁶

p⁶ = p⁶

SUMMARY

p × p × p × p × p × p = p⁶ = (p²)³

p² × p² × p² = p⁶ = (p²)³

p⁶ = (p²)³

Therefore, 3 expressions are equivalent to (p²)³. Option C gives the correct answer to the question.

6 0

3 years ago

If x represents an even integer, write expressions in terms of x that represent the next four consecutive even integers. If the

Rufina [12.5K]

Answer:

16.2, 18,2, 20.2, 22.2, 24.2

Step-by-step explanation:

Let

$x$

represent an even interger.

Remeber that even intergers have a distance of 2 from each other.

So next four consecutive intergers are

$x + 2$

$x + 4$

$x + 6$

and

$x + 8$

Part 2: Five consective intergers have a sum of 101, and qe must find the numbers so

$x + x + 2 + x + 4 + x + 6 + x + 8 = 101$

$5x + 20 = 101$

$5x = 81$

$x= 16.2$

3 0

2 years ago

Math Questions :3 thank uu <3

coldgirl [10]

14. 1.5, 10 <- Answer
15. 5,1 <- Answer

Proof 14

Solve the following system:
{2 x - y = -7 | (equation 1)
4 x - y = -4 | (equation 2)
Swap equation 1 with equation 2:
{4 x - y = -4 | (equation 1)
2 x - y = -7 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{4 x - y = -4 | (equation 1)
0 x - y/2 = -5 | (equation 2)
Multiply equation 2 by -2:
{4 x - y = -4 | (equation 1)
0 x+y = 10 | (equation 2)
Add equation 2 to equation 1:
{4 x+0 y = 6 | (equation 1)
0 x+y = 10 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 3/2 | (equation 1)
0 x+y = 10 | (equation 2)
Collect results:
Answer: {x = 1.5
y = 10

Proof 15.

Solve the following system:
{5 x + 7 y = 32 | (equation 1)
8 x + 6 y = 46 | (equation 2)
Swap equation 1 with equation 2:
{8 x + 6 y = 46 | (equation 1)
5 x + 7 y = 32 | (equation 2)
Subtract 5/8 × (equation 1) from equation 2:{8 x + 6 y = 46 | (equation 1)
0 x+(13 y)/4 = 13/4 | (equation 2)
Divide equation 1 by 2:
{4 x + 3 y = 23 | (equation 1)
0 x+(13 y)/4 = 13/4 | (equation 2)
Multiply equation 2 by 4/13:
{4 x + 3 y = 23 | (equation 1)
0 x+y = 1 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{4 x+0 y = 20 | (equation 1)
0 x+y = 1 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 5 | (equation 1)
0 x+y = 1 | (equation 2)
Collect results:
Answer: {x = 5 y = 1

8 0

3 years ago