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3 years ago

Convert the angle 0=35° to radians

Mathematics

2 answers:

ahrayia [7]3 years ago

6 0

Answer:

7π /36

Step-by-step explanation:

wlad13 [49]3 years ago

4 0

There You Make Sure You Leave A Thanks

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What is the GCF of 28a^3 b and 16ab ? A)4ab B)4a3b C)28ab D)112a3b2

N76 [4]

28a⁴b: 2 · 2 · 7 · a · a · a · a · b
16ab: 2 · 2 · 2 · 2 · a · b

GCF(28a⁴b, 16ab) = 4ab

The answer is A.

7 0

3 years ago

Which parabola has the graph shown? I think the answer is C. however, I'm not 100% sure.

NemiM [27]

$x=m(y-k)^2+h\\\\(h,\ k)-the\ vertex$

We have the vertex (-4, -1), therefore we have:

$x=(y-(-1))^2-4\ \ \ |+4\\\\(x+4)=(y+1)^2$

7 0

3 years ago

3(4*5)=(3*4)5 what is thsi

Serggg [28]

This is the associative property. Basically if you move the parenthesis either to left or right you’ll still get the right answer. So 4 times 5 equals 20 and 20 times 3 equals 60. 3 x 4 equals 12 and 12 x 5 equals 60

8 0

2 years ago

Read 2 more answers

g The probability that a university graduate will be offered no jobs within a month of graduation is estimated to be 5%. The pro

dexar [7]

Answer:

49% probability that a graduate is offered fewer than two jobs

Step-by-step explanation:

We have these following probabilities:

5% probabilities of not being offered a job

44% probability of receiving one job offer

28% probability of received two job offers.

23% probability of receiving three job offers.

Determine the following probabilities: A. P(A graduate is offered fewer than two jobs)

Zero or one

5 + 44 = 49%

49% probability that a graduate is offered fewer than two jobs

8 0

2 years ago

Use the quadratic formula to solve the following equation -3x^2-x-3=0

tigry1 [53]

Answer:

$x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i$ are two roots of equation $-3 x^{2}-x-3=0$

Solution:

Need to solve given equation using quadratic formula.

$-3 x^{2}-x-3=0$

General form of quadratic equation is $a x^{2}+b x+c=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = -1 , a = -3 and c = -3

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(-1) \pm \sqrt{(-1)^{2}-4(-3)(-3)}}{2 \times-3}} \\\\ {x=-\frac{1}{6} \pm\left(-\frac{\sqrt{-35}}{6}\right)}\end{array}$

Since $b^{2}-4 a c$ is equal to -35, which is less than zero, so given equation will not have real roots and have complex roots.

$\begin{array}{l}{\text { Hence } x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i \text { are two roots of equation - }} \\ {3 x^{2}-x-3=0}\end{array}$

8 0

3 years ago