Answer:
(a) Approximate the percent error in computing the area of the circle: 4.5%
(b) Estimate the maximum allowable percent error in measuring the circumference if the error in computing the area cannot exceed 3%: 0.6 cm
Step-by-step explanation:
(a)
First we need to calculate the radius from the circumference:

I leave only one decimal as we need to keep significative figures
Now we proceed to calculate the error for the radius:


Again only one decimal because the significative figures
Now that we have the radius, we can calculate the area and the error:

Then we calculate the error:


Now we proceed to calculate the percent error:

(b)
With the previous values and equations, now we set our error in 3%, so we just go back changing the values:

Now we calculate the error for the radius:

Now we proceed with the error for the circumference:

Hello there,
I believe the answer would be 17×6 - 6(9+14)(6)/2 = 102 -414 = -312 but i am not 100% Sure!! Sorry if I am wrong!
Hope I helped
The exact value for the equation is true but I don't really think that's the question so anyways...
- 15.) The exact form for this equation is -13pi/3 and the decimal form -13.613...
- 16.) The exact form for this equation is 23pi/4 and the decimal form 18/064...
- 17.) The exact form is -7pi/2 as the decimal is -10.995...
- 18.) The exact is -29pi/6 and the decimal is -15.184...
Answer:
0.1225
Step-by-step explanation:
Given
Number of Machines = 20
Defective Machines = 7
Required
Probability that two selected (with replacement) are defective.
The first step is to define an event that a machine will be defective.
Let M represent the selected machine sis defective.
P(M) = 7/20
Provided that the two selected machines are replaced;
The probability is calculated as thus
P(Both) = P(First Defect) * P(Second Defect)
From tge question, we understand that each selection is replaced before another selection is made.
This means that the probability of first selection and the probability of second selection are independent.
And as such;
P(First Defect) = P (Second Defect) = P(M) = 7/20
So;
P(Both) = P(First Defect) * P(Second Defect)
PBoth) = 7/20 * 7/20
P(Both) = 49/400
P(Both) = 0.1225
Hence, the probability that both choices will be defective machines is 0.1225
So, first off it would help if you could define the terms irrational number and integer. Well, an irrational number is basically any real number that can't be expressed as a ratio of integers. They also cannot be represented by terminating or continuing decimals. And an integer is pretty much any number that cannot be written as a fraction or decimal, such as -2, 13, 257. It is not 2 and 1/2, or 4.75. Those would not be integers. Do you think you can figure out the difference?