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Blababa [14]
4 years ago
11

I have the are of the rectangle, but how can I find the area of the triangle?

Mathematics
2 answers:
Scilla [17]4 years ago
5 0

Answer:

Step-by-step explanation:

You first times the width by the height than divide by 2

oee [108]4 years ago
5 0

Answer:

Right hand side triangle: 2 square units

Left hand side triangle: 1.5 square units

Step-by-step explanation:

The area of a triangle is given by the equation A = 1/2 * base * height. For the left triangle, this means 1/2 * 2 * 1.5, which equals 1.5 For the right hand triangle, this is 1/2 * (8.5-4.5) * 2, which is 4.

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2 years ago
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Consider M, N, and P. collinear points on MP.
Kobotan [32]

Answer:

See explanation

Step-by-step explanation:

There are three possible cases:

1. Point N lies between M and P, then MN + NP = MP. Consider needed difference:

\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{NP}-\dfrac{MN}{MN+NP}=\dfrac{MN(MN+NP)-MN\cdot NP}{NP(MN+NP)}=\\ \\=\dfrac{MN^2+MN\cdot NP-MN\cdot NP}{NP(MN+NP)}=\dfrac{MN^2}{NP(MN+NP)}

2. Point N lies to the right from point P, then MP + PN = MN.  Consider needed difference:

\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MP+PN}{NP}-\dfrac{MP+PN}{MP}=\dfrac{MP}{NP}+1-1-\dfrac{NP}{MP}=\dfrac{MP^2-NP^2}{NP\cdot MP}

3. Point N lies to the left from point M, then NM + MP = NP. Consider needed difference:

\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{MN+MP}-\dfrac{MN}{MP}=\dfrac{MN\cdot MP-MN(MN+MP)}{MP(MN+MP)}=\\ \\=\dfrac{MN\cdot MP-MN^2-MN\cdot MP}{MP(MN+MP)}=\dfrac{-MN^2}{MP(MN+MP)}

3 0
3 years ago
When<br>4a-a×За + 7а<br>is simplified it is equivalent to​
Alexxx [7]

Answer:

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= 4a + -3a^2 + 7a

combine like terms

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3 years ago
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Total amount 
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163200
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3 years ago
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